Linux 在 ac 程序中运行 shell 命令
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Running a shell command in a c program
提问by wonnie
I want to run a shell command in my c program. But the thing is that i don't want to make my program wait until the command performed. No need to read the shell command's output (it returns no data anyway) So basically, is that possible?
我想在我的 c 程序中运行一个 shell 命令。但问题是我不想让我的程序等到命令执行。无需读取 shell 命令的输出（无论如何它不返回任何数据） 所以基本上，这可能吗？
采纳答案by Stefano Borini
fork()and system()is what you need
fork()并且system()是你所需要的
回答by rlc
Sure, just forkand exec: use forkto create a new process and, in the child process, use execto start the shell with your command. execvtakes the arguments you would normally give to the shell.
当然，只是fork和exec: 用于fork创建一个新进程，并且在子进程中，用于使用exec您的命令启动外壳程序。execv接受您通常会提供给 shell 的参数。
Your code could look like this:
您的代码可能如下所示：
pid_t child_pid = fork();
if (child_pid == 0)
{ // in child
/* set up arguments */
// launch here
execv("/bin/sh", args);
// if you ever get here, there's been an error - handle it
}
else if (child_pid < 0)
{ // handle error
}
the child process will send a SIGCHLDsignal when it dies. This code quoted from the POSIX standard (SUSv4) will handle that:
子进程SIGCHLD在它死亡时会发送一个信号。从 POSIX 标准 (SUSv4) 引用的这段代码将处理：
static void
handle_sigchld(int signum, siginfo_t *sinfo, void *unused)
{
int status;
/*
* Obtain status information for the child which
* caused the SIGCHLD signal and write its exit code
* to stdout.
*/
if (sinfo->si_code != CLD_EXITED)
{
static char msg[] = "wrong si_code\n";
write(2, msg, sizeof msg - 1);
}
else if (waitpid(sinfo->si_pid, &status, 0) == -1)
{
static char msg[] = "waitpid() failed\n";
write(2, msg, sizeof msg - 1);
}
else if (!WIFEXITED(status))
{
static char msg[] = "WIFEXITED was false\n";
write(2, msg, sizeof msg - 1);
}
else
{
int code = WEXITSTATUS(status);
char buf[2];
buf[0] = '0' + code;
buf[1] = '\n';
write(1, buf, 2);
}
}
回答by HymanMc
Try code like this:
试试这样的代码：
#include <stdlib.h>
#include <unistd.h>
int main(int argc, char ** argv)
{
if (!fork())
{
execv("ls", {"myDir"}); /* Your command with arguments instead of ls. */
}
}
回答by Jens
What about simply amping the command with system ("command &")?
简单地用 放大命令system ("command &")怎么样？
