Java EntityManager 没有持久性提供程序命名...错误

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时间:2020-08-12 11:27:16  来源:igfitidea点击:

No Persistence provider for EntityManager named... error

javahibernatejakarta-eejpapersistence.xml

提问by ebruszl

My persistence xml file is like that

我的持久化xml文件就是这样

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
    version="1.0">
    <persistence-unit name="hibernateEbru">     
        <provider>org.hibernate.ejb.HibernatePersistence</provider>     
        <class>com.hibernate.business_card</class> 
        <properties>            
            <property name="hibernate.hbm2ddl.auto" value="create" />           
            <property name="hibernate.show_sql" value="true" />         
            <property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect" />         
            <property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" />         
            <property name="hibernate.connection.username" value="root" />          
            <property name="hibernate.connection.password" value="2643" />          
            <property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/BusinessDb" /> 

        </properties>
    </persistence-unit>
</persistence>

Then I have my code calling it with this:

然后我让我的代码用这个调用它:

public class test {
    public static void main(String[] args) {
        EntityManagerFactory emf = Persistence.createEntityManagerFactory("hibernateEbru");

        EntityManager em = emf.createEntityManager();

        em.getTransaction().begin();

        business_card bc = new business_card();
        bc.setName("Ebru");

        em.persist(bc);

        em.getTransaction().commit();

        em.close();

        emf.close();

    }
}

I got the following error message:

我收到以下错误消息:

Exception in thread "main" javax.persistence.PersistenceException: No Persistence provider for EntityManager named hibernateEbru
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:56)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:34)
    at com.hibernate.test.main(test.java:8)

回答by cmd

You will need to move the persistence.xml file to an appropriate location

您需要将 persistence.xml 文件移动到适当的位置

From JPA spec:

从 JPA 规范:

A persistence.xml file defines a persistence unit. The persistence.xml file is located in the META-INF directory of the root of the persistence unit.

persistence.xml 文件定义了一个持久性单元。persistence.xml 文件位于持久性单元根目录的 META-INF 目录中。

The root of the persistence unit is the key here.

持久化单元的根是这里的关键。

If you are a non-Java EE app

如果您是非 Java EE 应用程序

The jar file or directory whose META-INF directory contains the persistence.xml file is termed the root of the persistence unit.

META-INF 目录包含persistence.xml 文件的jar 文件或目录称为持久性单元的根。

If you are in a Java EE app, the following are valid

如果您在 Java EE 应用程序中,以下内容是有效的

In Java EE environments, the root of a persistence unit must be one of the following:

  • an EJB-JAR file
  • the WEB-INF/classes directory of a WAR file[80]
  • a jar file in the WEB-INF/lib directory of a WAR file
  • a jar file in the EAR library directory
  • an application client jar file

在 Java EE 环境中,持久性单元的根必须是以下之一:

  • 一个 EJB-JAR 文件
  • WAR 文件的 WEB-INF/classes 目录 [80]
  • WAR文件的WEB-INF/lib目录下的jar文件
  • EAR 库目录中的 jar 文件
  • 应用程序客户端 jar 文件