Python 如何得到小数点后的数字？
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How to get numbers after decimal point?
提问by l--''''''---------''''''''''''
How do I get the numbers after a decimal point?
如何得到小数点后的数字？
For example, if I have 5.55, how do i get .55?
例如，如果我有5.55，我如何获得.55？
采纳答案by lllluuukke
An easy approach for you:
一个简单的方法给你：
number_dec = str(number-int(number))[1:]
回答by Jim Brissom
What about:
关于什么：
a = 1.3927278749291
b = a - int(a)
b
>> 0.39272787492910011
Or, using numpy:
或者，使用 numpy：
import numpy
a = 1.3927278749291
b = a - numpy.fix(a)
回答by jer
5.55 % 1
Keep in mind this won't help you with floating point rounding problems. I.e., you may get:
请记住，这不会帮助您解决浮点舍入问题。即，您可能会得到：
0.550000000001
Or otherwise a little off the 0.55 you are expecting.
或者比您期望的 0.55 稍微低一点。
回答by Juri Robl
Try Modulo:
尝试模数：
5.55%1 = 0.54999999999999982
回答by Kevin Lacquement
import math
orig = 5.55
whole = math.floor(orig) # whole = 5.0
frac = orig - whole # frac = 0.55
回答by Kevin Lacquement
Use floor and subtract the result from the original number:
使用 floor 并从原始数字中减去结果：
>> import math #gives you floor.
>> t = 5.55 #Give a variable 5.55
>> x = math.floor(t) #floor returns t rounded down to 5..
>> z = t - x #z = 5.55 - 5 = 0.55
回答by intuited
Using the decimalmodule from the standard library, you can retain the original precision and avoid floating point rounding issues:
使用decimal标准库中的模块，您可以保留原始精度并避免浮点舍入问题：
>>> from decimal import Decimal
>>> Decimal('4.20') % 1
Decimal('0.20')
As kindallnotesin the comments, you'll have to convert native floats to strings first.
回答by ghostdog74
>>> n=5.55
>>> if "." in str(n):
... print "."+str(n).split(".")[-1]
...
.55
回答by Romulus
Another crazy solution is (without converting in a string):
另一个疯狂的解决方案是（不转换成字符串）：
number = 123.456
temp = 1
while (number*temp)%10 != 0:
temp = temp *10
print temp
print number
temp = temp /10
number = number*temp
number_final = number%temp
print number_final
