ios 使用 NSURLRequest 请求

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时间:2020-08-30 17:47:33  来源:igfitidea点击:

Request with NSURLRequest

objective-ciosnsurlconnectionnsurlrequest

提问by Edelweiss

I'm trying do to an app which uses a database (actually in my localhost), I tried with ASIHTTPRequest but having so much troubles with iOS 5 (I learnt how to use ASIHTTPRequest form there : http://www.raywenderlich.com/2965/how-to-write-an-ios-app-that-uses-a-web-service

我正在尝试使用数据库(实际上在我的本地主机中)的应用程序,我尝试使用 ASIHTTPRequest 但在 iOS 5 上遇到了很多麻烦(我在那里学会了如何使用 ASIHTTPRequest 表单:http://www.raywenderlich.com /2965/how-to-write-an-ios-app-that-uses-a-web-service

Now i'm trying with the API provided by Apple : NSURLRequest / NSURLConnection etc,...

现在我正在尝试使用 Apple 提供的 API:NSURLRequest / NSURLConnection 等,...

I read the Apple online guide and make this first code :

我阅读了 Apple 在线指南并制作了第一个代码:

- (void)viewDidLoad
{

    [super viewDidLoad];

     // Do any additional setup after loading the view, typically from a nib.



    NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL

                                URLWithString:@"http://localhost:8888/testNSURL/index.php"]

                                cachePolicy:NSURLRequestUseProtocolCachePolicy

                                timeoutInterval:60.0];



    [request setValue:@"Hello world !" forKey:@"myVariable"];



    NSURLConnection *theConnection=[[NSURLConnection alloc] initWithRequest:request delegate:self];

    if (theConnection) {

        receiveData = [NSMutableData data];   

    }

}

I added the delegates needed by the API

我添加了 API 所需的委托

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data

- (void)connection:(NSURLConnection *)connection

- (void)connectionDidFinishLoading:(NSURLConnection *)connection

Here is my php code :

这是我的 php 代码:

<?php
if(isset($_REQUEST["myVariable"])) {
    echo $_REQUEST["myVariable"];
}
else    echo '$_REQUEST["myVariable"] not found';
?>

So what is wrong? When I start the app, it will immediately crash with this output :

那么有什么问题呢?当我启动应用程序时,它会立即崩溃并显示以下输出:

**

**

**> 2012-04-09 22:52:16.630 NSURLconnextion[819:f803] *** Terminating app
> due to uncaught exception 'NSUnknownKeyException', reason:
> '[<NSURLRequest 0x6b32bd0> setValue:forUndefinedKey:]: this class is
> not key value coding-compliant for the key myVariable.'
> *** First throw call stack: (0x13c8022 0x1559cd6 0x13c7ee1 0x9c0022 0x931f6b 0x931edb 0x2d20 0xd9a1e 0x38401 0x38670 0x38836 0x3f72a
> 0x10596 0x11274 0x20183 0x20c38 0x14634 0x12b2ef5 0x139c195 0x1300ff2
> 0x12ff8da 0x12fed84 0x12fec9b 0x10c65 0x12626 0x29dd 0x2945) terminate
> called throwing an exception**

**

**

I guess, it means that somethings is wrong with this line :

我想,这意味着这一行有问题:

[request setValue:@"Hello world !" forKey:@"myVariable"];

It actually works if I comment this line.

如果我评论这一行,它实际上有效。

My question is : How can I send datas to a PHP API, using NSURLRequest and NSURLConnexion?

我的问题是:如何使用 NSURLRequest 和 NSURLConnexion 将数据发送到 PHP API?

Thank you for helping.

感谢您的帮助。

P.S. By the way, I have poor knowledges about server, PHP ect,...

PS顺便说一句,我对服务器,PHP等,...的了解很少。

回答by Mirko Lindner

try this:

尝试这个:

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL

                            URLWithString:@"http://localhost:8888/testNSURL/index.php"]

                            cachePolicy:NSURLRequestUseProtocolCachePolicy

                            timeoutInterval:60.0];

[request setHTTPMethod:@"POST"];
NSString *postString = @"myVariable=Hello world !";
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];

NSURLConnection *theConnection=[[NSURLConnection alloc] initWithRequest:request delegate:self];

if (theConnection) {

    receiveData = [NSMutableData data];   

}

seen here https://stackoverflow.com/a/6149088/1317080

在这里看到https://stackoverflow.com/a/6149088/1317080

回答by Durai Amuthan.H

Try the below code it is one of the simple ways to consume a web service(json)

试试下面的代码,它是使用网​​络服务(json)的简单方法之一

NSURL *url = [NSURL URLWithString:@"yourURL"];

NSMutableURLRequest *urlReq=[NSMutableURLRequest requestWithURL:url];

NSURLResponse *response;

NSError *error = nil;

 NSData *receivedData = [NSURLConnection sendSynchronousRequest:urlReq
                                              returningResponse:&response
                                                         error:&error];
if(error!=nil)
{
   NSLog(@"web service error:%@",error);
}
else
{
 if(receivedData !=nil)
 {
    NSError *Jerror = nil;

    NSDictionary* json =[NSJSONSerialization
                         JSONObjectWithData:receivedData
                         options:kNilOptions
                         error:&Jerror];

   if(Jerror!=nil)
   {
    NSLog(@"json error:%@",Jerror);
   }
 }
}

Hope this helps.

希望这可以帮助。