Javascript regex 匹配（中间的随机字符串）
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Javascript regex match (random string in the middle)
提问by user2640648
I want to test if a string can match a pattern in javascript
我想测试一个字符串是否可以匹配 javascript 中的模式
problem is there is a random string in the middle pattern: "account/os/some_random_string/call_back"
问题是中间模式中有一个随机字符串：“account/os/ some_random_string/call_back”
so a string look like below will match
所以看起来像下面的字符串将匹配
var mystring = "account/os/1234567/call_back"
var mystring = "account/os/1234567/call_back"
thanks
谢谢
回答by Paul
You want a regex for starts with account/os/and ends with /call_back, here's one:
你想要一个以 开头account/os/和结尾的正则表达式/call_back，这是一个：
/^account\/os\/.*\/call_back$/
.*will match any random string (including the empty string.). If you want a minimum length on the random string you change the *:
.*将匹配任何随机字符串（包括空字符串。）。如果您想要随机字符串的最小长度，请更改*：
.* : 0 or more characters
.+ : 1 or more characters
.{n,} : n or more characters (replace n with an actual number)
回答by Silviu Burcea
Well, it depends. If you want every single character between account/os/ and /call_back, use this:
这要看情况。如果您想要 account/os/ 和 /call_back 之间的每个字符，请使用：
var randomStr = mystring.match(/account\/os\/(.*)\/call_back/)[1];
The match will return an array with 2 elements, the first one with the entire match, the 2nd one with the group (.*). If you are completely sure that you have at least one character there, replace * with +.
匹配将返回一个包含 2 个元素的数组，第一个包含整个匹配项，第二个包含组 (.*)。如果您完全确定那里至少有一个字符，请将 * 替换为 +。
If you know something more specific about the text you have to collect, here are some replacements for the .(dot is matching almost everything):
如果您对必须收集的文本有更具体的了解，这里有一些替代 .（点几乎匹配所有内容）：
[A-z] for any of A, B, .. , Y, Z, a, b, .. , y, z
[0-9] for any digit
You can mix then and go fancy, like this:
你可以混合然后去幻想，像这样：
[A-Ea-e0-36-8]
So, your pattern may look like this one:
因此，您的模式可能如下所示：
/account\/os\/([A-Ea-e0-36-8]*)\/call_back/
Your example have a number there, so you are probably looking for:
您的示例在那里有一个数字，因此您可能正在寻找：
/account\/os\/([0-9]*)\/call_back/
or
或者
/account\/os\/(\d*)\/call_back/
.. it's the same thing.
.. 这是同一件事。
Hope that helps.
希望有帮助。
Edit: What JS answer doesn't have a jsfiddle? http://jsfiddle.net/U2Jhw/
编辑：什么 JS 答案没有 jsfiddle？http://jsfiddle.net/U2Jhw/
