JAVA 中的网站/URL 验证正则表达式

Website/URL Validation Regex in JAVA

提问by Hao Ting

I need a regex string to match URL starting with "http://", "https://", "www.", "google.com"

我需要一个正则表达式字符串来匹配以“http://”、“https://”、“www.”、“google.com”开头的 URL

the code i tried using is:

我尝试使用的代码是：

//Pattern to check if this is a valid URL address
    Pattern p = Pattern.compile("(http://|https://)(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?");
    Matcher m;
    m=p.matcher(urlAddress);

but this code only can match url such as "http://www.google.com"

但此代码只能匹配诸如“ http://www.google.com”之类的网址

I know this ma be a dupicate question but i have tried all of the regex provided and it does not suit my requirement. Willl someone please help me? Thank you.

我知道这可能是一个重复的问题，但我已经尝试了所有提供的正则表达式，但它不符合我的要求。有人会帮助我吗？谢谢你。

采纳答案by Avinash Raj

You need to make (http://|https://)part in your regex as optional one.

您需要将(http://|https://)您的正则表达式作为可选的一部分。

^(http:\/\/|https:\/\/)?(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?$

DEMO

演示

回答by raghavsood33

Java compatible version of @Avinash's answer would be

@Avinash 答案的 Java 兼容版本是

//Pattern to check if this is a valid URL address
Pattern p = Pattern.compile("^(http://|https://)?(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?$");
Matcher m;
m=p.matcher(urlAddress);
boolean matches = m.matches();

回答by Raj Hassani

You can use the Apache commons library(org.apache.commons.validator.UrlValidator) for validating a url:

您可以使用 Apache 公共库（org.apache.commons.validator.UrlValidator）来验证 url：

String[] schemes = {"http","https"}.
UrlValidator urlValidator = new UrlValidator(schemes);

And use :-

并使用：-

 urlValidator.isValid(your url)

Then there is no need of regex.

那么就不需要正则表达式了。

Link:- https://commons.apache.org/proper/commons-validator/apidocs/org/apache/commons/validator/routines/UrlValidator.html

链接：- https://commons.apache.org/proper/commons-validator/apidocs/org/apache/commons/validator/routines/UrlValidator.html

回答by KnechtRootrecht

If you use Java, I recommend use this RegEx (I wrote it by myself):

如果你使用 Java，我推荐使用这个 RegEx（我自己写的）：

^(https?:\/\/)?(www\.)?([\w]+\.)+[??\w]{2,63}\/?$
"^(https?:\/\/)?(www\.)?([\w]+\.)+[??\w]{2,63}\/?$" // as Java-String

to explain:

解释：

• ^ = line start
• (https?://)? = "http://" or "https://" may occur.
• (www.)? = "www." may orrur.
• ([\w]+.)+ = a word ([a-zA-Z0-9]) has to occur one or more times. (extend here if you need special characters like ü, ?, ? or others in your URL - remember to use IDN.toASCII(url) if you use special characters. If you need to know which characters are legal in general: https://kb.ucla.edu/articles/what-characters-can-go-into-a-valid-http-url
• [??\w]{2,63} = a word ([a-zA-Z0-9]) with 2 to 63 characters has to occur exactly one time. (a TLD (top level domain (for example .com) can not be shorter than 2 or longer than 63 characters)
• /? = a "/"-character may occur. (some people or servers put a / at the end... whatever)
• $ = line end

• ^ = 行开始
• （https？：//）？= "http://" 或 "https://" 可能会出现。
• （万维网。）？=“万维网。” 可能orrur。
• ([\w]+.)+ = 一个词 ([a-zA-Z0-9]) 必须出现一次或多次。（如果您的 URL 中需要特殊字符，如 ü、?、? 或其他字符，请在此处扩展 - 如果您使用特殊字符，请记住使用 IDN.toASCII(url)。如果您需要知道哪些字符通常是合法的：https:/ /kb.ucla.edu/articles/what-c​​haracters-can-go-into-a-valid-http-url
• [??\w]{2,63} = 2 到 63 个字符的单词 ([a-zA-Z0-9]) 必须恰好出现一次。（TLD（顶级域（例如 .com）不能短于 2 个或长于 63 个字符）
• /? = 可能会出现“/”字符。（有些人或服务器在最后放了一个 / ......无论如何）
• $ = 行尾

-

——

If you extend it by special characters it could look like this:

如果用特殊字符扩展它，它可能如下所示：

^(https?:\/\/)?(www\.)?([\w\Q$-_+!*'(),%\E]+\.)+[??\w]{2,63}\/?$
"^(https?:\/\/)?(www\.)?([\w\Q$-_+!*'(),%\E]+\.)+[??\w]{2,63}\/?$" // as Java-String

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The answer of Avinash Raj is not fully correct.

Avinash Raj 的回答并不完全正确。

^(http:\/\/|https:\/\/)?(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?$

The dots are not escaped what means it matches with any character. Also my version is simpler and I never heard of a domain like "test..com" (which actually matches...)

点不会被转义，这意味着它与任何字符匹配。我的版本也更简单，我从来没有听说过像“test..com”这样的域（实际上匹配......）

Demo: https://regex101.com/r/vM7wT6/279

演示：https: //regex101.com/r/vM7wT6/279

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Edit: As I saw some people needing a regex which also matches servers directories I wrote this:

编辑：当我看到有些人需要一个也匹配服务器目录的正则表达式时，我写了这个：

^(https?:\/\/)?([\w\Q$-_+!*'(),%\E]+\.)+(\w{2,63})(:\d{1,4})?([\w\Q/$-_+!*'(),%\E]+\.?[\w])*\/?$

while this may not be the best one, since I didn't spend too much time with it, maybe it helps someone. You can see how it works here: https://regex101.com/r/vM7wT6/700It also matches urls like "hello.to/test/whatever.cgi"

虽然这可能不是最好的，因为我没有花太多时间在它上面，也许它对某人有帮助。你可以在这里看到它是如何工作的：https: //regex101.com/r/vM7wT6/700 它还匹配像“hello.to/test/whatever.cgi”这样的网址

回答by darkwinter

pattern="w{3}\.[a-z]+\.?[a-z]{2,3}(|\.[a-z]{2,3})"

this will only accept addresses like e.g www.google.com & www.google.co.in

这将只接受诸如 www.google.com 和 www.google.co.in 之类的地址

回答by Anabel Berumen

//I use that

//我用那个

static boolean esURL(String cadena){

    boolean bandera = false;

    bandera = cadena.matches("\b(https://?|ftp://|file://|www.)[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]");

    return bandera;
}