Laravel 5.6 - 在控制器中按名称获取路由
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Laravel 5.6 - Get Route By Name In Controller
提问by heady12
Within my login controller there is a hardcoded URL string which sets where to redirect to once the user has logged in. I am trying to make this dynamic by getting the route by name:
在我的登录控制器中，有一个硬编码的 URL 字符串，用于设置用户登录后重定向到的位置。我试图通过按名称获取路由来使其动态化：
protected $redirectTo = '/home';
Updated To:
更新为：
protected $redirectTo = route('home');
However the above give the following error:
但是上面给出了以下错误：
FatalErrorException (E_UNKNOWN) Constant expression contains invalid operations
FatalErrorException (E_UNKNOWN) 常量表达式包含无效操作
Is it possible to get the URL to the route by its name?
是否可以通过名称获取路由的 URL？
回答by DigitalDrifter
You can use
您可以使用
request()->route()->getName()
To get the url you would use
要获取您将使用的网址
request()->url()
And the path
和路径
request()->path()
Current route method
当前路线方法
request->route()->getActionMethod()
In the case of redirectToyou can override the function:
在redirectTo你可以覆盖函数的情况下：
protected function redirectTo() {
return route('foo.bar');
}
回答by eamirgh
You have to define a route named homelike this:
Route::get('/home', 'HomeController@index')->name('home');
or Route::get('/home', ['as' => 'home', 'uses' => 'HomeController@index']);
你必须定义一个home像这样命名的路由：
Route::get('/home', 'HomeController@index')->name('home');
或Route::get('/home', ['as' => 'home', 'uses' => 'HomeController@index']);
回答by Sourav
Another way to get route url
另一种获取路由url的方法
$route_url = \Request::route()->getURLByName("name of the route");
回答by Jonathon
Your problem is that you're not allowed to use a function call when declaring a property in your class. You should use your controller's constructor to set it:
您的问题是在类中声明属性时不允许使用函数调用。您应该使用控制器的构造函数来设置它：
class LoginController extends Controller
{
protected $redirectTo = '/home';
public function __construct()
{
$this->middleware('guest')->except('logout');
$this->redirectTo = route('home');
}
}
Alternatively, you can define a redirectTomethod which returns the location that you want the user to be redirected to after a successful login. You can then remove the $redirectToproperty altogether:
或者，您可以定义一个redirectTo方法，该方法返回您希望用户在成功登录后重定向到的位置。然后，您可以$redirectTo完全删除该属性：
class LoginController extends Controller
{
public function __construct()
{
$this->middleware('guest')->except('logout');
}
public function redirectTo()
{
return route('home');
}
}
回答by Adnan Mumtaz
protected $redirectTo = route('home');
You cannot assign a function to property. That's why you are getting this error.
您不能将功能分配给属性。这就是您收到此错误的原因。
you can do this in your constructor like
你可以在你的构造函数中这样做
public function __construct(){
$this->redirectTo = route('home')
}
回答by Mohammed Aktaa
This is the way which i use and it will work with you.just put this function in your LoginController to override authenticated function.
这是我使用的方式，它将与您一起使用。只需将此功能放在您的 LoginController 中即可覆盖经过身份验证的功能。
protected function authenticated(Request $request, $user)
{
return redirect()->route('your_route_name');
}
