typescript 获取打字稿中变量的名称
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Get name of variable in typescript
提问by Kenneth Bo Christensen
How can I get a variables name in typescript? I want something like this:
如何在打字稿中获取变量名称？我想要这样的东西：
var name = "Foo";
alert(getVariableName(name)); //Prints "name"
回答by Titian Cernicova-Dragomir
Expanding on basarat's answer, you need to create function that takes as a parameter a function that will contain the access to your variable. Because in JavaScript you can access the code of any function it then becomes a simple matter of using a regex to extract the variable name.
扩展 basarat 的答案，您需要创建一个函数，该函数将一个函数作为参数，该函数将包含对您的变量的访问。因为在 JavaScript 中您可以访问任何函数的代码，所以使用正则表达式来提取变量名称变得很简单。
var varExtractor = new RegExp("return (.*);");
export function getVariableName<TResult>(name: () => TResult) {
var m = varExtractor.exec(name + "");
if (m == null) throw new Error("The function does not contain a statement matching 'return variableName;'");
return m[1];
}
var foo = "";
console.log(getVariableName(() => foo));
回答by basarat
TypeScript is JavaScript at runtime. So the same limitations as there apply : Get the 'name' of a variable in Javascript
TypeScript 是运行时的 JavaScript。因此，同样的限制适用：在 Javascript 中获取变量的“名称”
However you can do stuff like
但是你可以做类似的事情
alert(getVariableName(()=>name))
Here you would parse the body of the function passed into getVariableName and get that as a string.
在这里，您将解析传递给 getVariableName 的函数体并将其作为字符串获取。
回答by Daniel Earwicker
One approach is to store such values in an object:
一种方法是将这些值存储在一个对象中：
var o = {
firstName: "Homer",
lastName: "Simpson"
};
We can't get the name of o, but we can get the names (or "keys") of its two properties:
我们无法获取 的名称o，但我们可以获取其两个属性的名称（或“键”）：
var k = Object.keys(o);
console.log(k[0]); // prints "firstName"
回答by Alon
Expanding Cernicova-Dragomir's answer:
扩展 Cernicova-Dragomir 的答案：
Expanding on basarat's answer, you need to create function that takes as a parameter a function that will contain the access to your variable. Because in JavaScript you can access the code of any function it then becomes a simple matter of using a regex to extract the variable name.
扩展 basarat 的答案，您需要创建一个函数，该函数将一个函数作为参数，该函数将包含对您的变量的访问。因为在 JavaScript 中您可以访问任何函数的代码，所以使用正则表达式来提取变量名称变得很简单。
to also support a field of an object:
还支持对象的字段：
var varExtractor = new RegExp("(.*)");
export function getVariableName<TResult>(getVar: () => TResult) {
var m = varExtractor.exec(getVar + "");
if (m == null)
throw new Error("The function does not contain a statement matching 'return variableName;'");
var fullMemberName = m[1];
var memberParts = fullMemberName.split('.');
return memberParts[memberParts.length-1];
}
var foo = { bar: "" };
var varName = getVariableName(() => foo.bar ); //prints "bar"
Notice that I've deleted the "return" because it doesn't work on Node.js when targeting ES6.
请注意，我删除了“return”，因为它在面向 ES6 时不适用于 Node.js。
