使用 paise 支持将印度货币数字转换为单词的 Javascript 函数
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时间：2020-10-28 00:21:04 来源:igfitidea点击:
Javascript function to convert indian currency numbers to words with paise support
提问by Hardik Thaker
Is there any faster solution than this?
还有比这更快的解决方案吗？
After spending some time in googling and playing with other's code, I made a quick fix and reusable function works well for numbers up to 99,99,99,999.
在花了一些时间在谷歌搜索和玩其他人的代码之后，我做了一个快速修复和可重用的函数，对于高达 99,99,99,999 的数字来说效果很好。
number2text(1234.56);will return ONE THOUSAND TWO HUNDRED AND THIRTY-FOUR RUPEE AND FIFTY-SIX PAISE ONLY.
number2text(1234.56);会回来ONE THOUSAND TWO HUNDRED AND THIRTY-FOUR RUPEE AND FIFTY-SIX PAISE ONLY。
function number2text(value) {
var fraction = Math.round(frac(value)*100);
var f_text = "";
if(fraction > 0) {
f_text = "AND "+convert_number(fraction)+" PAISE";
}
return convert_number(value)+" RUPEE "+f_text+" ONLY";
}
function frac(f) {
return f % 1;
}
function convert_number(number)
{
if ((number < 0) || (number > 999999999))
{
return "NUMBER OUT OF RANGE!";
}
var Gn = Math.floor(number / 10000000); /* Crore */
number -= Gn * 10000000;
var kn = Math.floor(number / 100000); /* lakhs */
number -= kn * 100000;
var Hn = Math.floor(number / 1000); /* thousand */
number -= Hn * 1000;
var Dn = Math.floor(number / 100); /* Tens (deca) */
number = number % 100; /* Ones */
var tn= Math.floor(number / 10);
var one=Math.floor(number % 10);
var res = "";
if (Gn>0)
{
res += (convert_number(Gn) + " CRORE");
}
if (kn>0)
{
res += (((res=="") ? "" : " ") +
convert_number(kn) + " LAKH");
}
if (Hn>0)
{
res += (((res=="") ? "" : " ") +
convert_number(Hn) + " THOUSAND");
}
if (Dn)
{
res += (((res=="") ? "" : " ") +
convert_number(Dn) + " HUNDRED");
}
var ones = Array("", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX","SEVEN", "EIGHT", "NINE", "TEN", "ELEVEN", "TWELVE", "THIRTEEN","FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN");
var tens = Array("", "", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY","SEVENTY", "EIGHTY", "NINETY");
if (tn>0 || one>0)
{
if (!(res==""))
{
res += " AND ";
}
if (tn < 2)
{
res += ones[tn * 10 + one];
}
else
{
res += tens[tn];
if (one>0)
{
res += ("-" + ones[one]);
}
}
}
if (res=="")
{
res = "zero";
}
return res;
}
回答by Mahesh Kathiriya
INDIAN PRICECURRENCY BY WORDS BASED ON GIVEN NUMBER
基于给定数字的单词印度价格货币
125,00,00,000
125,00,00,000
One Hundred and Twenty Five Crore
125 千万
function price_in_words(price) {
var sglDigit = ["Zero", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"],
dblDigit = ["Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"],
tensPlace = ["", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"],
handle_tens = function(dgt, prevDgt) {
return 0 == dgt ? "" : " " + (1 == dgt ? dblDigit[prevDgt] : tensPlace[dgt])
},
handle_utlc = function(dgt, nxtDgt, denom) {
return (0 != dgt && 1 != nxtDgt ? " " + sglDigit[dgt] : "") + (0 != nxtDgt || dgt > 0 ? " " + denom : "")
};
var str = "",
digitIdx = 0,
digit = 0,
nxtDigit = 0,
words = [];
if (price += "", isNaN(parseInt(price))) str = "";
else if (parseInt(price) > 0 && price.length <= 10) {
for (digitIdx = price.length - 1; digitIdx >= 0; digitIdx--) switch (digit = price[digitIdx] - 0, nxtDigit = digitIdx > 0 ? price[digitIdx - 1] - 0 : 0, price.length - digitIdx - 1) {
case 0:
words.push(handle_utlc(digit, nxtDigit, ""));
break;
case 1:
words.push(handle_tens(digit, price[digitIdx + 1]));
break;
case 2:
words.push(0 != digit ? " " + sglDigit[digit] + " Hundred" + (0 != price[digitIdx + 1] && 0 != price[digitIdx + 2] ? " and" : "") : "");
break;
case 3:
words.push(handle_utlc(digit, nxtDigit, "Thousand"));
break;
case 4:
words.push(handle_tens(digit, price[digitIdx + 1]));
break;
case 5:
words.push(handle_utlc(digit, nxtDigit, "Lakh"));
break;
case 6:
words.push(handle_tens(digit, price[digitIdx + 1]));
break;
case 7:
words.push(handle_utlc(digit, nxtDigit, "Crore"));
break;
case 8:
words.push(handle_tens(digit, price[digitIdx + 1]));
break;
case 9:
words.push(0 != digit ? " " + sglDigit[digit] + " Hundred" + (0 != price[digitIdx + 1] || 0 != price[digitIdx + 2] ? " and" : " Crore") : "")
}
str = words.reverse().join("")
} else str = "";
return str
}
console.log(price_in_words(1250000000));
console.log(price_in_words(9999999999));回答by asfak mohamed
The second comment has the solution. Just use:
第二条评论有解决方案。只需使用：
var num =129000.9889;
var splittedNum =num.toString().split('.')
var nonDecimal=splittedNum[0]
var decimal=splittedNum[1]
var value=price_in_words(Number(nonDecimal))+" and
"+price_in_words(Number(decimal))+" paise"
回答by sandyhrk
function convertNumberToWords(amount) {
var words = new Array();
words[0] = '';
words[1] = 'One';
words[2] = 'Two';
words[3] = 'Three';
words[4] = 'Four';
words[5] = 'Five';
words[6] = 'Six';
words[7] = 'Seven';
words[8] = 'Eight';
words[9] = 'Nine';
words[10] = 'Ten';
words[11] = 'Eleven';
words[12] = 'Twelve';
words[13] = 'Thirteen';
words[14] = 'Fourteen';
words[15] = 'Fifteen';
words[16] = 'Sixteen';
words[17] = 'Seventeen';
words[18] = 'Eighteen';
words[19] = 'Nineteen';
words[20] = 'Twenty';
words[30] = 'Thirty';
words[40] = 'Forty';
words[50] = 'Fifty';
words[60] = 'Sixty';
words[70] = 'Seventy';
words[80] = 'Eighty';
words[90] = 'Ninety';
amount = amount.toString();
var atemp = amount.split(".");
var number = atemp[0].split(",").join("");
var n_length = number.length;
var words_string = "";
if (n_length <= 9) {
var n_array = new Array(0, 0, 0, 0, 0, 0, 0, 0, 0);
var received_n_array = new Array();
for (var i = 0; i < n_length; i++) {
received_n_array[i] = number.substr(i, 1);
}
for (var i = 9 - n_length, j = 0; i < 9; i++, j++) {
n_array[i] = received_n_array[j];
}
for (var i = 0, j = 1; i < 9; i++, j++) {
if (i == 0 || i == 2 || i == 4 || i == 7) {
if (n_array[i] == 1) {
n_array[j] = 10 + parseInt(n_array[j]);
n_array[i] = 0;
}
}
}
value = "";
for (var i = 0; i < 9; i++) {
if (i == 0 || i == 2 || i == 4 || i == 7) {
value = n_array[i] * 10;
} else {
value = n_array[i];
}
if (value != 0) {
words_string += words[value] + " ";
}
if ((i == 1 && value != 0) || (i == 0 && value != 0 && n_array[i + 1] == 0)) {
words_string += "Crores ";
}
if ((i == 3 && value != 0) || (i == 2 && value != 0 && n_array[i + 1] == 0)) {
words_string += "Lakhs ";
}
if ((i == 5 && value != 0) || (i == 4 && value != 0 && n_array[i + 1] == 0)) {
words_string += "Thousand ";
}
if (i == 6 && value != 0 && (n_array[i + 1] != 0 && n_array[i + 2] != 0)) {
words_string += "Hundred and ";
} else if (i == 6 && value != 0) {
words_string += "Hundred ";
}
}
words_string = words_string.split(" ").join(" ");
}
return words_string;
}
