Python 如何判断一个整数是偶数还是奇数
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时间：2020-08-18 12:03:09 来源:igfitidea点击:
How to determine if an integer is even or odd
提问by user2033235
def is_odd(num):
# Return True or False, depending on if the input number is odd.
# Odd numbers are 1, 3, 5, 7, and so on.
# Even numbers are 0, 2, 4, 6, and so on.
I'm wondering what you would do from here to get those answers.
我想知道你会怎么做才能得到这些答案。
回答by NPE
def is_odd(num):
return num % 2 != 0
Symbol "%" is called modulo and returns the remainder of division of one number by another.
符号“%”称为模数，返回一个数除以另一个数的余数。
回答by unutbu
def is_odd(num):
return num & 0x1
It is not the most readable, but it is quick:
它不是最易读的，但它很快：
In [11]: %timeit is_odd(123443112344312)
10000000 loops, best of 3: 164 ns per loop
versus
相对
def is_odd2(num):
return num % 2 != 0
In [10]: %timeit is_odd2(123443112344312)
1000000 loops, best of 3: 267 ns per loop
Or, to make the return values the same as is_odd:
或者，使返回值与is_odd：
def is_odd3(num):
return num % 2
In [21]: %timeit is_odd3(123443112344312)
1000000 loops, best of 3: 205 ns per loop
