Javascript 如何使用moment.js计算Javascript中两个日期之间的“工作日”数？

How to calculate Number of 'Working days' between two dates in Javascript using moment.js?

提问by Ali Shaan

How to calculate the number of working days between two dates in JavaScript using moment.js. I have a working formula that calculate these days, but the formula does not satisfies all conditions:

如何使用 moment.js 在 JavaScript 中计算两个日期之间的工作日数。我有一个计算这些天的工作公式，但该公式不满足所有条件：

here is my code:

这是我的代码：

var start= moment(data[x].start_date);
                var end= moment(data[x].est_end_date);
                var difference= end.diff(start, 'days');
                var workingDays= Math.round((difference/7)*5);
//data[x] is for iterating over a loop

I get five days per 7 days here because saturday and sunday are considered as NON-Working days, but this formula will fail if the count of the days were started from sunday or saturday.

我在这里每 7 天有 5 天，因为星期六和星期日被视为非工作日，但如果从星期日或星期六开始计算天数，则此公式将失败。

Please any one could help in this regard that what necessary changes must be done in order to avoid this problem.

请任何人都可以在这方面提供帮助，必须进行哪些必要的更改才能避免此问题。

回答by Kokizzu

Just divide it into 3 parts.. first week, last week and the in between, something like this:

只需将其分为 3 部分.. 第一周、上周和中间，如下所示：

function workday_count(start,end) {
  var first = start.clone().endOf('week'); // end of first week
  var last = end.clone().startOf('week'); // start of last week
  var days = last.diff(first,'days') * 5 / 7; // this will always multiply of 7
  var wfirst = first.day() - start.day(); // check first week
  if(start.day() == 0) --wfirst; // -1 if start with sunday 
  var wlast = end.day() - last.day(); // check last week
  if(end.day() == 6) --wlast; // -1 if end with saturday
  return wfirst + Math.floor(days) + wlast; // get the total
} //              ^ EDIT: if days count less than 7 so no decimal point

The test code

测试代码

var ftest = {date:'2015-02-0',start:1,end:7};
var ltest = {date:'2015-02-2',start:2,end:8};
var f = 'YYYY-MM-DD';
for(var z=ftest.start; z<=ftest.end; ++z) {
  var start = moment(ftest.date + z);
  for(var y=ltest.start; y<=ltest.end; ++y) {
    var end = moment(ltest.date + y);
    var wd = workday_count(start,end);
    console.log('from: '+start.format(f),'to: '+end.format(f),'is '+wd+' workday(s)');
  }
}

Output of test code:

测试代码输出：

from: 2015-02-01 to: 2015-02-22 is 15 workday(s)
from: 2015-02-01 to: 2015-02-23 is 16 workday(s)
from: 2015-02-01 to: 2015-02-24 is 17 workday(s)
from: 2015-02-01 to: 2015-02-25 is 18 workday(s)
from: 2015-02-01 to: 2015-02-26 is 19 workday(s)
from: 2015-02-01 to: 2015-02-27 is 20 workday(s)
from: 2015-02-01 to: 2015-02-28 is 20 workday(s)
from: 2015-02-02 to: 2015-02-22 is 15 workday(s)
from: 2015-02-02 to: 2015-02-23 is 16 workday(s)
from: 2015-02-02 to: 2015-02-24 is 17 workday(s)
from: 2015-02-02 to: 2015-02-25 is 18 workday(s)
from: 2015-02-02 to: 2015-02-26 is 19 workday(s)
from: 2015-02-02 to: 2015-02-27 is 20 workday(s)
from: 2015-02-02 to: 2015-02-28 is 20 workday(s)
from: 2015-02-03 to: 2015-02-22 is 14 workday(s)
from: 2015-02-03 to: 2015-02-23 is 15 workday(s)
from: 2015-02-03 to: 2015-02-24 is 16 workday(s)
from: 2015-02-03 to: 2015-02-25 is 17 workday(s)
from: 2015-02-03 to: 2015-02-26 is 18 workday(s)
from: 2015-02-03 to: 2015-02-27 is 19 workday(s)
from: 2015-02-03 to: 2015-02-28 is 19 workday(s)
from: 2015-02-04 to: 2015-02-22 is 13 workday(s)
from: 2015-02-04 to: 2015-02-23 is 14 workday(s)
from: 2015-02-04 to: 2015-02-24 is 15 workday(s)
from: 2015-02-04 to: 2015-02-25 is 16 workday(s)
from: 2015-02-04 to: 2015-02-26 is 17 workday(s)
from: 2015-02-04 to: 2015-02-27 is 18 workday(s)
from: 2015-02-04 to: 2015-02-28 is 18 workday(s)
from: 2015-02-05 to: 2015-02-22 is 12 workday(s)
from: 2015-02-05 to: 2015-02-23 is 13 workday(s)
from: 2015-02-05 to: 2015-02-24 is 14 workday(s)
from: 2015-02-05 to: 2015-02-25 is 15 workday(s)
from: 2015-02-05 to: 2015-02-26 is 16 workday(s)
from: 2015-02-05 to: 2015-02-27 is 17 workday(s)
from: 2015-02-05 to: 2015-02-28 is 17 workday(s)
from: 2015-02-06 to: 2015-02-22 is 11 workday(s)
from: 2015-02-06 to: 2015-02-23 is 12 workday(s)
from: 2015-02-06 to: 2015-02-24 is 13 workday(s)
from: 2015-02-06 to: 2015-02-25 is 14 workday(s)
from: 2015-02-06 to: 2015-02-26 is 15 workday(s)
from: 2015-02-06 to: 2015-02-27 is 16 workday(s)
from: 2015-02-06 to: 2015-02-28 is 16 workday(s)
from: 2015-02-07 to: 2015-02-22 is 10 workday(s)
from: 2015-02-07 to: 2015-02-23 is 11 workday(s)
from: 2015-02-07 to: 2015-02-24 is 12 workday(s)
from: 2015-02-07 to: 2015-02-25 is 13 workday(s)
from: 2015-02-07 to: 2015-02-26 is 14 workday(s)
from: 2015-02-07 to: 2015-02-27 is 15 workday(s)
from: 2015-02-07 to: 2015-02-28 is 15 workday(s)

回答by Juan García

I use a simple function to accomplish that. Maybe is not the most efficient but it works. It doesn't require Moment.js. it's just Javascript.

我使用一个简单的函数来完成它。也许不是最有效的，但它有效。它不需要 Moment.js。这只是Javascript。

function getNumWorkDays(startDate, endDate) {
    var numWorkDays = 0;
    var currentDate = new Date(startDate);
    while (currentDate <= endDate) {
        // Skips Sunday and Saturday
        if (currentDate.getDay() !== 0 && currentDate.getDay() !== 6) {
            numWorkDays++;
        }
        currentDate = currentDate.addDays(1);
    }
    return numWorkDays;
}

To addDays, I use the following function:

为了addDays，我使用以下功能：

Date.prototype.addDays = function (days) {
    var date = new Date(this.valueOf());
    date.setDate(date.getDate() + days);
    return date;
};

回答by Jo?o Bruno Abou Hatem de Liz

I've made an adaptation to Kokizzu answer, in order to fix a Summer Time problem. In Brazilian Timezone (GMT -3), the difference between 17/10/2017 and 18/10/2017 was -2.71 instead of 2.

为了解决夏令时问题，我对 Kokizzu 的回答进行了改编。在巴西时区 (GMT -3) 中，17/10/2017 和 18/10/2017 之间的差异是 -2.71 而不是 2。

The start of the week was 15/10/2017 00:00 UTC or 14/10/2017 21:00-03:00

一周的开始时间为 15/10/2017 00:00 UTC 或 14/10/2017 21:00-03:00

The end of the week was 22/10/2017 00:00 UTC or 21/10/2017 22:00-02:00 (Summer Time)

本周结束时间为 22/10/2017 00:00 UTC 或 21/10/2017 22:00-02:00（夏令时）

Therefore, instead of 7, the difference between "first" and "last" variable in days was 6 (or 8, depending on your Timezone).

因此，而不是 7，“第一个”和“最后一个”变量之间的天数差异是 6（或 8，取决于您的时区）。

The code fixed is below:

修复的代码如下：

start = moment(start).utc().add(start.utcOffset(), 'm'); // Ignore timezones
end = moment(end).utc().add(end.utcOffset(), 'm'); // Ignore timezones

var first = start.clone().endOf('week'); // end of first week
var last = end.clone().startOf('week'); // start of last week

// Fixing Summer Time problems
firstCorrection = moment(first).utc().add(60, 'm').toDate(); //
var days = last.diff(firstCorrection,'days') * 5 / 7; // this will always multiply of 7

var wfirst = first.day() - start.day(); // check first week
if(start.day() == 0) --wfirst; // -1 if start with sunday
var wlast = end.day() - last.day(); // check last week
if(end.day() == 6) --wlast; // -1 if end with saturday
return wfirst + days + wlast; // get the total (subtract holidays if needed)

回答by simonberry

I found kokizzu's answer didn't work if days were in the same week (e.g. sun to sat), so settled for this instead :

我发现如果几天在同一周（例如太阳到坐），kokizzu 的回答不起作用，所以解决了这个问题：

    function calcBusinessDays(startDate, endDate) { 
      var day = moment(startDate);
      var businessDays = 0;

      while (day.isSameOrBefore(endDate,'day')) {
        if (day.day()!=0 && day.day()!=6) businessDays++;
        day.add(1,'d');
      }
      return businessDays;
    }

回答by Rhode

By using momentjs, it's possible this way:

通过使用momentjs，可以这样：

private calculateWorkdays(startDate: Date, endDate: Date): number {
// + 1 cause diff returns the difference between two moments, in this case the day itself should be included.

const totalDays: number = moment(endDate).diff(moment(startDate), 'days') + 1;
const dayOfWeek = moment(startDate).isoWeekday();
let totalWorkdays = 0;

for (let i = dayOfWeek; i < totalDays + dayOfWeek; i++) {
    if (i % 7 !== 6 && i % 7 !== 0) {
      totalWorkdays++;
    }
  }
  return totalWorkdays;
}

回答by Adem Aygun

you can try this(without loop):

你可以试试这个（没有循环）：

  function getBusinessDays(endDate, startDate) {
    var lastDay = moment(endDate);
    var firstDay = moment(startDate);
    let calcBusinessDays = 1 + (lastDay.diff(firstDay, 'days') * 5 -
      (firstDay.day() - lastDay.day()) * 2) / 7;

    if (lastDay.day() == 6) calcBusinessDays--;//SAT
    if (firstDay.day() == 0) calcBusinessDays--;//SUN

    return calcBusinessDays;
  }

Original Source

原始来源