C++ 错误：“::main”必须返回“int”
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ERROR: '::main' must return 'int'
提问by SPLASH
This my main function:
这是我的主要功能：
void main(int argc, char **argv)
{
if (argc >= 4)
{
ProcessScheduler *processScheduler;
std::cout <<
"Running algorithm: " << argv[2] <<
"\nWith a CSP of: " << argv[3] <<
"\nFilename: " << argv[1] <<
std::endl << std::endl;
if (argc == 4)
{
processScheduler = new ProcessScheduler(
argv[2],
atoi(argv[3])
);
}
else
{
processScheduler = new ProcessScheduler(
argv[2],
atoi(argv[3]),
atoi(argv[4]),
atoi(argv[5])
);
}
processScheduler -> LoadFile(argv[1]);
processScheduler -> RunProcesses();
GanntChart ganntChart(*processScheduler);
ganntChart.DisplayChart();
ganntChart.DisplayTable();
ganntChart.DisplaySummary();
system("pause");
delete processScheduler;
}
else
{
PrintUsage();
}
}
The error I get when I compile is this:
我编译时得到的错误是这样的：
Application.cpp:41:32: error: '::main' must return 'int'
Application.cpp:41:32: 错误：'::main' 必须返回 'int'
It's a void function how can I return int and how do I fix it?
这是一个 void 函数，我如何返回 int 以及如何修复它？
回答by Michael
Try doing this:
尝试这样做：
int main(int argc, char **argv)
{
// Code goes here
return 0;
}
The return 0;returns a 0 to the operating system which means that the program executed successfully.
所述return 0;返回一个0到操作系统，这意味着程序成功执行。
回答by Nick Pavini
C++ requires main()to be of type int.
C++ 要求main()类型为int.
回答by renonsz
Function is declared as int main(..);, so change your voidreturn value to int, and return 0at the end of the main function.
函数被声明为int main(..);，因此将void返回值更改为int，并return 0在主函数的末尾。
