Python 如何获取子目录名称列表
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How to get list of subdirectories names
提问by Andersson
There is a directory that contains folders as well as files of different formats.
有一个目录，其中包含文件夹以及不同格式的文件。
import os
my_list = os.listdir('My_directory')
will return full content of files and folders names. I can use, for example, endswith('.txt')method to select just text files names, but how to get list of just folders names?
将返回文件和文件夹名称的完整内容。例如，我可以使用endswith('.txt')方法仅选择文本文件名，但如何获取仅文件夹名称的列表？
采纳答案by jhoepken
I usually check for directories, while assembling a list in one go. Assuming that there is a directory called foo, that I would like to check for sub-directories:
我通常会检查目录，同时一次性组装一个列表。假设有一个名为 的目录foo，我想检查子目录：
import os
output = [dI for dI in os.listdir('foo') if os.path.isdir(os.path.join('foo',dI))]
回答by Frerich Raabe
Just use os.path.isdiron the results returned by os.listdir, as in:
只需os.path.isdir在 返回的结果上使用os.listdir，如下所示：
def listdirs(path):
return [d for d in os.listdir(path) if os.path.isdir(os.path.join(path, d))]
回答by coincoin
That should work :
那应该工作：
my_dirs = [d for d in os.listdir('My_directory') if os.path.isdir(os.path.join('My_directory', d))]
回答by Avinash Raj
You may use os.walk
您可以使用 os.walk
for i,j,y in os.walk('.'):
print(i)
回答by user1016274
os.walkalready splits files and folders up into different lists, and works recursively:
os.walk已经将文件和文件夹分成不同的列表，并递归地工作：
for root,dirs,_ in os.walk('.'):
for d in dirs:
print os.path.join(root,d)
