从 C++ 列表库中打印出列表的内容
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Printing out contents of a list from the c++ list library
提问by Drew L. Facchiano
I wanted to print out the contents of a list for a simple program I'm writing. I'm using the built in list library
我想打印出我正在编写的一个简单程序的列表内容。我正在使用内置列表库
#include <list>
however, I've no idea how to print out the contents of this list in order to test/check the data within. How do I do this?
但是，我不知道如何打印此列表的内容以测试/检查其中的数据。我该怎么做呢？
回答by Jerry Coffin
If you have a recent compiler (one that includes at least a few C++11 features), you can avoid dealing with iterators (directly) if you want. For a list of "small" things like ints, you might do something like this:
如果您有最新的编译器（至少包含一些 C++11 功能的编译器），则可以根据需要避免（直接）处理迭代器。对于像ints这样的“小”事物列表，您可以执行以下操作：
#include <list>
#include <iostream>
int main() {
list<int> mylist = {0, 1, 2, 3, 4};
for (auto v : mylist)
std::cout << v << "\n";
}
If the items in the list are larger (specifically, large enough that you'd prefer to avoid copying them), you'd want to use a reference instead of a value in the loop:
如果列表中的项目较大（具体来说，足够大以至于您希望避免复制它们），您需要在循环中使用引用而不是值：
for (auto const &v : mylist)
std::cout << v << "\n";
回答by Martin York
Try:
尝试：
#include <list>
#include <algorithm>
#include <iterator>
#include <iostream>
int main()
{
list<int> l = {1,2,3,4};
// std::copy copies items using iterators.
// The first two define the source iterators [begin,end). In this case from the list.
// The last iterator defines the destination where the data will be copied too
std::copy(std::begin(l), std::end(l),
// In this case the destination iterator is a fancy output iterator
// It treats a stream (in this case std::cout) as a place it can put values
// So you effectively copy stuff to the output stream.
std::ostream_iterator<int>(std::cout, " "));
}
回答by john
For instance, for a list of int
例如，对于一个 int 列表
list<int> lst = ...;
for (list<int>::iterator i = lst.begin(); i != lst.end(); ++i)
cout << *i << endl;
If you are working with list you better get used to iterators pretty quickly.
如果您正在使用列表，您最好很快就习惯迭代器。
回答by Brandon Ling
You use an Iterator.
您使用迭代器。
for(list<type>::iterator iter = list.begin(); iter != list.end(); iter++){
cout<<*iter<<endl;
}
回答by Captain Obvlious
You can use iterators and a small forloop for this. Since you are simply outputting the values in the list you should use const_iteratorrather than iteratorto prevent accidentally modifying the object referenced by the iterator.
您可以for为此使用迭代器和一个小循环。由于您只是输出列表中的值，因此您应该使用const_iterator而不是iterator防止意外修改迭代器引用的对象。
Here is an example of how to iterate through variable varthat is a list of int's
这是一个如何迭代变量的示例，该变量var是int's的列表
for (list<int>::const_iterator it = var.begin(); it != var.end(); ++it)
cout << *it << endl;
