如何获取和更改 URL 变量 PHP
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How to get and change URL variable PHP
提问by CaffeineShots
Hi could anyone help me with this I have a URL like
嗨，谁能帮我解决这个问题，我有一个类似的网址
parent/child/a=1&b=2$c=3
then I have a link that would add variable to that URL
然后我有一个链接，可以向该 URL 添加变量
<a href="<?php echo $_SERVER["REQUEST_URI"]."&d=test1";?>">LINK 1</a>
<a href="<?php echo $_SERVER["REQUEST_URI"]."&d=test2";?>">LINK 2</a>
every time I click my link the variable d to URL keep on reproducing like this
每次我单击我的链接时，变量 d 到 URL 都会像这样继续复制
parent/child/a=1&b=2&c=3&d=test2&d=test2&d=test2&d=test1&d=test1
I know that the $_SERVER["REQUEST_URI"] keep getting the current URL that is why I get that result. I have tried the some of properties of $_SERVER[""]. What I like is to change the d variable value, any idea how to do it. Any response is well appreciated.Thanks!
我知道 $_SERVER["REQUEST_URI"] 不断获取当前 URL，这就是我得到该结果的原因。我已经尝试了 $_SERVER[""] 的一些属性。我喜欢的是改变 d 变量值，不知道怎么做。任何回应都非常感谢。谢谢！
回答by Michael Eugene Yuen
$query = $_GET;
// replace parameter(s)
$query['d'] = 'new_value';
// rebuild url
$query_result = http_build_query($query);
// new link
<a href="<?php echo $_SERVER['PHP_SELF']; ?>?<?php echo $query_result; ?>">Link</a>
回答by Vinoth Babu
Try with the below expression, It Should Work
尝试使用以下表达式，它应该可以工作
preg_replace("#&d=.*&#", '&d=newvalue&', $_SERVER['REQUEST_URI'])
回答by ihorsl
modify_url_query($url, array('limit' => 50));
My function for modifying query in url
我在 url 中修改查询的功能
function modify_url_query($url, $mod){
$purl = parse_url($url);
$params = array();
if (($query_str=$purl['query']))
{
parse_str($query_str, $params);
foreach($params as $name => $value)
{
if (isset($mod[$name]))
{
$params[$name] = $mod[$name];
unset($mod[$name]);
}
}
}
$params = array_merge($params, $mod);
$ret = "";
if ($purl['scheme'])
{
$ret = $purl['scheme'] . "://";
}
if ($purl['host'])
{
$ret .= $purl['host'];
}
if ($purl['path'])
{
$ret .= $purl['path'];
}
if ($params)
{
$ret .= '?' . http_build_query($params);
}
if ($purl['fragment'])
{
$ret .= "#" . $purl['fragment'];
}
return $ret;
}
回答by Venkat Kotra
To remove repeated addition of query parameter do the below
要删除重复添加查询参数，请执行以下操作
// parse the url
$pathInfo = parse_url($_SERVER['REQUEST_URI']);
$queryString = $pathInfo['query'];
// convert the query parameters to an array
parse_str($queryString, $queryArray);
// add the new query parameter into the array
$queryArray['d'] = 1;
// build the new query string
$newQueryStr = http_build_query($queryArray);
// construct new url
?>
<a href="<?php echo $pathInfo['host'].'?'.$newQueryStr;?>">LINK 1</a>
回答by Vikas Chauhan
function replaceUrlParameters($url = '', $newParams = array()){
if($url){
$urlArray = parse_url($url);
$queryString = $urlArray['query'];
parse_str($queryString, $queryParams);
$queryParams = array_merge($queryParams, $newParams);
$urlArray['query'] = http_build_query($queryParams);
if(!empty($urlArray)){
$url = $urlArray['scheme'].'://'.$urlArray['host'].$urlArray['path'].'?'.$urlArray['query'];
}
}
return $url;
}
// $newParams = array of new parameters or old parameters with new value
$replacedUrl = replaceUrlParameters($url, $newParams);
Suppose you have url like :- <?php echo $_SERVER["REQUEST_URI"]."&a=test1&b=test2";?>and you want to replace parameter b's value to test3 then just pass this url and an array with the same index with new value. for ex- <?$url = $_SERVER["REQUEST_URI"]."&a=test1&b=test2";?> <? $newParams = ['b' => 'test3']?>then you will get - <? $_SERVER["REQUEST_URI"]."&a=test1&b=test3";?>
假设您有类似 :- 的 url，<?php echo $_SERVER["REQUEST_URI"]."&a=test1&b=test2";?>并且您想将参数 b 的值替换为 test3，然后只需传递此 url 和一个具有相同索引的数组和新值。对于前 -<?$url = $_SERVER["REQUEST_URI"]."&a=test1&b=test2";?> <? $newParams = ['b' => 'test3']?>那么你会得到 -<? $_SERVER["REQUEST_URI"]."&a=test1&b=test3";?>
回答by Pasi Matalam?ki
Couldn't still find fitting solution myself, so created one..
自己仍然无法找到合适的解决方案，所以创建了一个..
static function changeParameters($url, $parameters)
{
$urlParts = parse_url($url);
$url = "";
if (isset($urlParts['scheme'])) {
$url .= $urlParts['scheme'] . "://";
}
if (isset($urlParts['host'])) {
$url .= $urlParts['host'];
}
if (isset($urlParts['path'])) {
$url .= $urlParts['path'];
}
$query = isset($urlParts['query']) ? $urlParts['query'] : "";
$urlParameters = explode("&", $query);
$urlParameterValuesByKey = new stdClass();
foreach ($urlParameters as $urlParameter) {
$equalsIndex = strrpos($urlParameter, "=");
if ($equalsIndex) {
$urlParameterValuesByKey->{substr($urlParameter, 0, $equalsIndex)} = substr($urlParameter, $equalsIndex + 1);
} else {
$urlParameterValuesByKey->{$urlParameter} = null;
}
}
foreach ($parameters as $key => $value) {
if(!is_string($value)) {
unset($urlParameterValuesByKey->{$key});
} else {
$urlParameterValuesByKey->{$key} = $value;
}
}
$query = "";
foreach ($urlParameterValuesByKey as $key => $value) {
if (strlen($query) === 0) {
$query .= "?";
}
if (strlen($query) > 1) {
$query .= "&";
}
if (is_string($value)) {
$query .= $key . "=" . $value;
} else {
$query .= $key;
}
}
$url .= $query;
return $url;
}
Uses stdClass instead of associative array, because associative arrays does some funky stuff for the keys before setting them, as described here.
使用 stdClass 而不是关联数组，因为关联数组在设置键之前为键做了一些时髦的事情，如here所述。
回答by Code L?ver
Here you have not take care of the double quotation. Replace that with the following code and then check.
这里你没有处理双引号。将其替换为以下代码，然后检查。
<a href="<?php echo 'http://'.$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'].'&d=test1';?>">LINK 1</a>
And also check in firebug that what URL is in href each time.
并且还检查萤火虫每次在href 中的URL 是什么。
