Python 交换 numpy 数组中的两个值。
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Swap two values in a numpy array.
提问by Gioelelm
Is there something more efficient than the following code to swap two values of a numpy 1D array?
是否有比以下代码更有效的方法来交换 numpy 一维数组的两个值？
input_seq = arange(64)
ix1 = randint(len(input_seq))
ixs2 = randint(len(input_seq))
temp = input_seq[ix2]
input_seq[ix2] = input_seq[ix1]
input_seq[ix1] = temp
采纳答案by Ffisegydd
You can use tuple unpacking. Tuple unpacking allows you to avoid the use of a temporary variable in your code (in actual fact I believe the Python code itself uses a temp variable behind the scenes but it's at a much lower level and so is much faster).
您可以使用元组解包。元组解包允许您避免在代码中使用临时变量（实际上我相信 Python 代码本身在幕后使用了一个临时变量，但它的级别要低得多，因此速度要快得多）。
input_seq[ix1], input_seq[ix2] = input_seq[ix2], input_seq[ix1]
I have flagged this question as a duplicate, the answer in the dupe posthas a lot more detail.
我已将此问题标记为重复，dupe 帖子中的答案有更多详细信息。
回答by Lewistrick
I see you're using numpy arrays. In that case, you can also do this:
我看到你在使用 numpy 数组。在这种情况下，您也可以这样做：
input_seq[[ix1, ix2]] = input_seq[[ix2, ix1]]
