如何在java中迭代JSONArray

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时间:2020-08-11 03:42:15  来源:igfitidea点击:

How to iterate JSONArray in java

javajsonparsingarrays

提问by Kathirvel Appusamy

I would like to extract the values from JSONArray. JSONArray has N number of rows and columns.

我想从 JSONArray 中提取值。JSONArray 有 N 个行和列。

        ObjectMapper mapper = new ObjectMapper();
        DynamicForm dynamicForm = new DynamicForm();
        dynamicForm = dynamicForm.bindFromRequest();
        Dynamic dynamic = dynamicForm.get(); 
        //List<OneModel> list = new ArrayList<OneModel>();
        //List iterate=new ArrayList();

        String data = dynamic.getData().get("content").toString();
        try {
            JSONArray jsonArray = new JSONArray(data);
            for (int i = 0; i < jsonArray.length(); i++) {
                System.out.println(jsonArray.get(i));
        } }catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }   

Its resulting as follows.

其结果如下。

["1001432","05-KALENJI-P1229","KALENJI","2","2014-11-09 09:37:14.379482",""],
["1001432","05-KALENJI-P1228","KALENJI","1","2014-11-09 09:37:14.379482",""],
["1001432","05-KALENJI-P1227","KALENJI","5","2014-11-09 09:37:14.379482",""]

I would like to extract one by one values and assign it to variable. for example 1001432,05-KALENJI-P1229,KALENJI,2,2014-11-09 09:37:14.379482. So that i can process each values. Please any one help me in the same

我想一一提取值并将其分配给变量。例如 1001432,05-KALENJI-P1229,KALENJI,2,2014-11-09 09:37:14.379482。这样我就可以处理每个值。请任何人帮助我

采纳答案by Krunal Indrodiya

You can use the following code:

您可以使用以下代码:

//put your json in the string variable "data"

//把你的json放在字符串变量“data”中

JSONArray jsonArray=new JSONArray(data);
            if(jsonArray!=null && jsonArray.length()>0){
                for (int i = 0; i < jsonArray.length(); i++) {
                    JSONArray childJsonArray=jsonArray.optJSONArray(i);
                    if(childJsonArray!=null && childJsonArray.length()>0){
                        for (int j = 0; j < childJsonArray.length(); j++) {
                            System.out.println(childJsonArray.optString(j));
                        }
                    }
                }
            }

回答by HymansOnF1re

Your can iterate over the array via a loop and get your objects like this:

您可以通过循环遍历数组并获得如下对象:

 JsonObject home = array.getJsonObject(index); //use index to iterate
 String num = home.getString("number"); //make number a static final variable

The "number" is the name for the value, which was originally put in with

“数字”是值的名称,它最初与

.add("number", someString);

Greets.

问候。

edit: I recommend to read the docu: Oracle Docand this, too.

编辑:我建议您也阅读文档:Oracle Doc这个。

回答by jmn

It looks like the JSON array is 2 dimensional. Try this:

看起来 JSON 数组是二维的。尝试这个:

JSONArray outerArray = new JSONArray(data);
for (int i = 0; i < outerArray.length(); i++) {
    JSONArray innerArray = outerArray.getJSONArray(i);

    for (int j = 0; j < outerArray.length(); j++) {
        System.out.println(innerArray.get(j));
    }
}