是否有 Java 包来处理构建 URL？
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Is there a Java package to handle building URLs?
提问by Bialecki
What I'm looking for specifically is some code in Java that will take a Mapobject and convert it into a query string that I can append to a URL I return. I'm sure there's a library that does this and much more, but I can't find it with a quick Google search. Anyone know of one that will do this?
我要特别寻找的是 Java 中的一些代码，它将获取一个Map对象并将其转换为查询字符串，我可以将其附加到我返回的 URL 中。我确信有一个图书馆可以做到这一点以及更多，但我无法通过快速的谷歌搜索找到它。有谁知道一个可以做到这一点？
采纳答案by miku
I found apache httpcomponentsto be a solid and versatile library for dealing with HTTP in Java. However, here's a sample class, which might suffice for building URL query strings:
我发现apache httpcomponents是一个可靠且通用的库，用于在 Java 中处理 HTTP。但是，这里有一个示例类，它可能足以构建 URL 查询字符串：
import java.net.URLEncoder;
public class QueryString {
private String query = "";
public QueryString(HashMap<String, String> map) {
Iterator it = mp.entrySet().iterator();
while (it.hasNext()) {
Map.Entry pairs = (Map.Entry)it.next();
query += URLEncoder.encode(pairs.getKey(), "utf-8") + "=" +
URLEncoder.encode(pairs.getValue(), "utf-8");
if (it.hasNext()) { query += "&"; }
}
}
public QueryString(Object name, Object value) {
query = URLEncoder.encode(name.toString(), "utf-8") + "=" +
URLEncoder.encode(value.toString(), "utf-8");
}
public QueryString() { query = ""; }
public synchronized void add(Object name, Object value) {
if (!query.trim().equals("")) query += "&";
query += URLEncoder.encode(name.toString(), "utf-8") + "=" +
URLEncoder.encode(value.toString(), "utf-8");
}
public String toString() { return query; }
}
Usage:
用法：
HashMap<String, String> map = new HashMap<String, String>();
map.put("hello", "world");
map.put("lang", "en");
QueryString q = new QueryString(map);
System.out.println(q);
// => "hello=world&lang=en"
回答by Thraidh
Try URIBuilderfrom Apache Http Compoments(HttpClient 4).
从Apache Http 组件(HttpClient 4)尝试URIBuilder。
It does not actually take a map, but is well suited for building URIs.
它实际上并不需要地图，但非常适合构建 URI。
回答by Reverend Gonzo
There's thisonline, so you can simply call any of:
有这个在线，所以你可以简单地调用任何一个：
InputStream serverInput = post(URL url, Map parameters);
InputStream serverInput = post(URL url, Map parameters);
InputStream serverInput = post(URL url, Map cookies, Map parameters);
InputStream serverInput = post(URL url, String[] cookies, Object[] parameters);
InputStream serverInput = post(URL url, Object[] parameters).
He provides the source code too.
他也提供了源代码。
