java C++“对象”类
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C++ "Object" class
提问by user142852
In Java, there is a generic class called "Object", in which all classes are a subclass of. I am trying to make a linked list library (for a school project), and I have managed it to make it work for only one type, but not multiple, so is there anything similar to that?
在Java中，有一个泛型类叫做“Object”，其中所有的类都是其子类。我正在尝试制作一个链表库（用于学校项目），并且我已经设法使其仅适用于一种类型，而不适用于多种类型，那么有没有类似的东西？
EDIT: I would post the code, but I don't have it on me at this time.
编辑：我会发布代码，但目前我没有。
回答by Luchian Grigore
There's no generic base class in C++, no.
C++ 中没有通用基类，没有。
You can implement your own and derive your classes from it, but you have to keep collections of pointers (or smart pointers) to take advantage of polymorphism.
您可以实现自己的类并从中派生类，但是您必须保留指针（或智能指针）的集合以利用多态性。
EDIT: After re-analyzing your question, I have to point out std::list.
编辑：重新分析你的问题后，我必须指出std::list。
If you want a list which you can specialize on multiple types, you use templates (and std::listis a template):
如果您想要一个可以专用于多种类型的列表，您可以使用模板（并且std::list是一个模板）：
std::list<classA> a;
std::list<classB> b;
If you want a list which can hold different types in a single instance, you take the base class approach:
如果您想要一个可以在单个实例中包含不同类型的列表，您可以采用基类方法：
std::list<Base*> x;
回答by MuffinMan
class Object{
protected:
void * Value;
public:
template <class Type>
void operator = (Type Value){
this->Value = (void*)Value;
}
template <>
void operator = <string>(string Value){
this->Value = (void*)Value.c_str();
}
template <class Type>
bool operator == (Type Value2){
return (int)(void*)Value2==(int)(void*)this->Value;
}
template<>
bool operator == <Object> (Object Value2){
return Value2.Value==this->Value;
}
template <class ReturnType>
ReturnType Get(){
return (ReturnType)this->Value;
}
template <>
string Get(){
string str = (const char*)this->Value;
return str;
}
template <>
void* Get(){
return this->Value;
}
void Print(){
cout << (signed)this->Value << endl;
}
};
Then make a subclass of it
然后创建它的子类
