javascript 如何使用单选按钮切换 div 可见性?
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How to toggle div visibility using radio buttons?
提问by Peter
I'm working on a project in which I have to toggle the visibility of a <div>
.
我正在做一个项目,我必须在其中切换<div>
.
I've got the following code:
我有以下代码:
<input type="radio" name="type" value="1"> Personal
<input type="radio" name="type" value="2"> Business
<div class="business-fields">
<input type="text" name="company-name">
<input type="text" name="vat-number">
</div>
I would like to togle the business-fields div. So, if none of the radio buttons, or the 'personal' radio button is selected: The div should be hidden. If the 'business' radio button is selected, I want it to show.
我想切换业务领域 div。因此,如果没有选择任何单选按钮或“个人”单选按钮:应该隐藏 div。如果选择了“业务”单选按钮,我希望它显示出来。
Currently, I am using this code:
目前,我正在使用此代码:
$("input[name='type']").click(function() {
var status = $(this).val();
if (status == 2) {
$(".business-fields").show();
} else {
$(".business-fields").hide();
}
});
However, I was wondering if I can do this using the .toggle() function.
但是,我想知道是否可以使用 .toggle() 函数来做到这一点。
回答by Akxe
I usually tend not to use JS if possible, therefore here comes a HTML+CSS way approach.
如果可能的话,我通常倾向于不使用 JS,因此这里有一种 HTML+CSS 方式方法。
.bussines-type .business-fields {
display: none;
}
.bussines-type input[value="2"]:checked ~ .business-fields {
display: block;
}
<div class="bussines-type">
<input id="bt1" type="radio" name="type" value="1">
<label for="bt1"> Personal</label>
<input id="bt2" type="radio" name="type" value="2">
<label for="bt2"> Business</label>
<div class="business-fields">
<input type="text" placeholder="Company name" name="company-name">
<input type="text" placeholder="Vat number" name="vat-number">
</div>
</div>
The ~
stands for any siblings, that are after the element we defined before the ~
sign.
The~
代表任何兄弟姐妹,在我们在~
符号之前定义的元素之后。
回答by David says reinstate Monica
I'd suggest using the change
event, and supplying a Boolean switch to the toggle()
method, which will show the jQuery collection of elements if the switch evaluates to true
, and hide them if it evaluates to false
:
我建议使用该change
事件,并为该toggle()
方法提供一个布尔开关,如果开关计算为true
,它将显示元素的 jQuery 集合,如果计算为,则隐藏它们false
:
// select the relevant <input> elements, and using on() to bind a change event-handler:
$('input[name="type"]').on('change', function() {
// this, in the anonymous function, refers to the changed-<input>:
// select the element(s) you want to show/hide:
$('.business-fields')
// pass a Boolean to the method, if the numeric-value of the changed-<input>
// is exactly equal to 2 and that <input> is checked, the .business-fields
// will be shown:
.toggle(+this.value === 2 && this.checked);
// trigger the change event, to show/hide the .business-fields element(s) on
// page-load:
}).change();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>
<input type="radio" name="type" value="1">Personal</label>
<label>
<input type="radio" name="type" value="2">Business</label>
<div class="business-fields">
<input type="text" name="company-name">
<input type="text" name="vat-number">
</div>
Incidentally, note I've also wrapped the associated text, to indicate the radio-button's purpose, inside of a <label>
element to directly associate that text with the <input>
, so clicking the text checks the <input>
automatically.
顺便说一句,请注意,我还包装了关联文本,以指示单选按钮的用途,在<label>
元素内部直接将该文本与 关联<input>
,因此单击文本会<input>
自动检查。
References:
参考:
回答by SimarjeetSingh Panghlia
Try this one
试试这个
<input type="radio" name="type" value="1" checked ="true"> Personal
<input type="radio" name="type" value="2"> Business
<div class="business-fields">
<input type="text" name="company-name">
<input type="text" name="vat-number">
</div>
.business-fields{
display: none;
}
$("input[name='type']").change(function() {
$(".business-fields").toggle();
});
回答by Ollie_W
.show and .hide are pretty slow. https://twitter.com/paul_irish/status/564443848613847040
.show 和 .hide 很慢。 https://twitter.com/paul_irish/status/564443848613847040
It's better to toggle a css class on and off with javascript. Set the css of the class to {visibility: hidden} or {display: none}
最好使用 javascript 打开和关闭 css 类。将类的 css 设置为 {visibility: hidden} 或 {display: none}
回答by Bhojendra Rauniyar
You may use like this:
你可以这样使用:
$("input[name='type']").change(function() {
var status = $(this).val();
if (status != 2) {
$(".business-fields").hide();
} else {
$(".business-fields").show();
}
});
回答by TECHNOMAN
use the below code
使用下面的代码
<script>
$(function(){
$(":radio[value=1]").click(function(){
var isVisible = $( ".business-fields" ).is( ":visible" );
if(isVisible==true)
$('.business-fields').toggle();
});
$(":radio[value=2]").click(function(){
var isVisible = $( ".business-fields" ).is( ":visible" );
if(isVisible==false)
$('.business-fields').toggle();
});
});
</script>
AND HTML is-
并且 HTML 是-
<input name="type" type="radio" value="1" >Personal
<input type="radio" name="type" value="2" checked="checked"> Business
<div class="business-fields">
<input type="text" name="company-name">
<input type="text" name="vat-number">
</div>
回答by linuxdan
Possibly a more elegant solution, It's a bit more readable in my opinion, and and as @Ollie_W points out it might be more performant that toggle (show/hide).
可能是一个更优雅的解决方案,在我看来它更具可读性,并且正如@Ollie_W 指出的那样,切换(显示/隐藏)可能会更高效。
$('input[name="type"]').on('change', function(event) {
var radioButton = $(event.currentTarget),
isBusiness = radioButton.val() === 'business' && radioButton.prop('checked');
$('.business-fields').toggleClass('hidden', !isBusiness);
}).change();
.hidden {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>
<input type="radio" name="type" value="personal">Personal</label>
<label>
<input type="radio" name="type" value="business">Business</label>
<div class="business-fields hidden">
<input type="text" name="company-name">
<input type="text" name="vat-number">
</div>