Python 获取用户输入的数字列表
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Get a list of numbers as input from the user
提问by Underyx
I tried to use raw_input()to get a list of numbers, however with the code
我试图用来raw_input()获取数字列表，但是使用代码
numbers = raw_input()
print len(numbers)
the input [1,2,3]gives a result of 7, so I guess it interprets the input as if it were a string. Is there any direct way to make a list out of it? Maybe I could use re.findallto extract the integers, but if possible, I would prefer to use a more Pythonic solution.
输入[1,2,3]的结果为7，所以我猜它会将输入解释为字符串。有什么直接的方法可以从中列出清单吗？也许我可以re.findall用来提取整数，但如果可能的话，我更愿意使用更 Pythonic 的解决方案。
采纳答案by greentec
In Python 3.x, use this.
在 Python 3.x 中，使用它。
a = [int(x) for x in input().split()]
Example
例子
>>> a = [int(x) for x in input().split()]
3 4 5
>>> a
[3, 4, 5]
>>>
回答by Sven Marnach
It is much easier to parse a list of numbers separated by spaces rather than trying to parse Python syntax:
解析由空格分隔的数字列表比尝试解析 Python 语法要容易得多：
Python 3:
蟒蛇3：
s = input()
numbers = list(map(int, s.split()))
Python 2:
蟒蛇2：
s = raw_input()
numbers = map(int, s.split())
回答by Karl Knechtel
eval(a_string)evaluates a string as Python code. Obviously this is not particularly safe. You can get safer (more restricted) evaluation by using the literal_evalfunction from the astmodule.
eval(a_string)将字符串计算为 Python 代码。显然这不是特别安全。通过使用模块中的literal_eval函数，您可以获得更安全（更受限制）的评估ast。
raw_input()is called that in Python 2.x because it gets raw, not "interpreted" input. input()interprets the input, i.e. is equivalent to eval(raw_input()).
raw_input()在 Python 2.x 中被称为是因为它是原始的，而不是“解释的”输入。input()解释输入，即相当于eval(raw_input())。
In Python 3.x, input()does what raw_input()used to do, and you must evaluate the contents manually if that's what you want (i.e. eval(input())).
在 Python 3.x 中，input()做以前raw_input()做的事情，如果这是您想要的（即eval(input())），您必须手动评估内容。
回答by Sean Vieira
You can use .split()
您可以使用 .split()
numbers = raw_input().split(",")
print len(numbers)
This will still give you strings, but it will be a list of strings.
这仍然会给你字符串，但它将是一个字符串列表。
If you need to map them to a type, use list comprehension:
如果需要将它们映射到类型，请使用列表理解：
numbers = [int(n, 10) for n in raw_input().split(",")]
print len(numbers)
If you want to be able to enter in anyPython type and have it mapped automatically andyou trust your users IMPLICITLYthen you can use eval
如果你希望能够在进入任何Python类型，并自动映射和你信任你的用户的隐式，那么你可以使用eval
回答by Hans
Try this:
尝试这个：
numbers = raw_input()
numberlist = list(numbers)
回答by Logan
you can pass a string representation of the list to json:
您可以将列表的字符串表示传递给 json：
import json
str_list = raw_input("Enter in a list: ")
my_list = json.loads(str_list)
user enters in the list as you would in python: [2, 34, 5.6, 90]
用户像在 python 中一样输入列表： [2, 34, 5.6, 90]
回答by Achintha Avin
Answer is trivial. try this.
答案是微不足道的。尝试这个。
x=input()
x=input()
Suppose that [1,3,5,'aA','8as']are given as the inputs
假设[1,3,5,'aA','8as']作为输入给出
print len(x)
print len(x)
this gives an answer of 5
这给出了 5 的答案
print x[3]
print x[3]
this gives 'aA'
这给 'aA'
回答by WolfGangM
You can use this function (with int type only) ;)
您可以使用此函数（仅限 int 类型）；)
def raw_inputList(yourComment):
listSTR=raw_input(yourComment)
listSTR =listSTR[1:len(listSTR)-1]
listT = listSTR.split(",")
listEnd=[]
for caseListT in listT:
listEnd.append(int(caseListT))
return listEnd
This function return your list (with int type) !
此函数返回您的列表（int 类型）！
Example :
例子 ：
yourList=raw_inputList("Enter Your List please :")
If you enter
如果你输入
"[1,2,3]"
then
然后
yourList=[1,2,3]
回答by xarvier
try this one ,
试试这个，
n=int(raw_input("Enter length of the list"))
l1=[]
for i in range(n):
a=raw_input()
if(a.isdigit()):
l1.insert(i,float(a)) #statement1
else:
l1.insert(i,a) #statement2
If the element of the list is just a number the statement 1 will get executed and if it is a string then statement 2 will be executed. In the end you will have an list l1 as you needed.
如果列表的元素只是一个数字，则语句 1 将被执行，如果它是一个字符串，则语句 2 将被执行。最后，您将根据需要获得一个列表 l1。
回答by Jutta
You just need to typeraw_input().split()and the default split() is that values are split by a whitespace.
您只需要输入raw_input().split()，默认的 split() 是值被一个空格分割。
