c# Array.FindAllIndexOf 其中FindAll IndexOf

c# Array.FindAllIndexOf which FindAll IndexOf

提问by Eric Yin

I know c# has Array.FindAlland Array.IndexOf.

我知道 c# 有Array.FindAll和Array.IndexOf.

Is there a Array.FindAllIndexOfwhich returns int[]?

是否有Array.FindAllIndexOf返回int[]？

采纳答案by Nikhil Agrawal

string[] myarr = new string[] {"s", "f", "s"};

int[] v = myarr.Select((b,i) => b == "s" ? i : -1).Where(i => i != -1).ToArray();

This will return 0, 2

这将返回 0, 2

If the value does not exist in the array then it will return a int[0].

如果数组中不存在该值，则它将返回一个 int[0]。

make an extension method of it

对其进行扩展方法

public static class EM
{
    public static int[] FindAllIndexof<T>(this IEnumerable<T> values, T val)
    {
        return values.Select((b,i) => object.Equals(b, val) ? i : -1).Where(i => i != -1).ToArray();
    }
}

and call it like

并称之为

string[] myarr = new string[] {"s", "f", "s"};

int[] v = myarr.FindAllIndexof("s");

回答by Pranay Rana

You can write something like :

你可以这样写：

string[] someItems = { "cat", "dog", "purple elephant", "unicorn" }; 
var selectedItems = someItems.Select((item, index) => new{
    ItemName = item,
    Position = index});

or

或者

var Items = someItems.Select((item, index) => new{
    ItemName = item,
    Position = index}).Where(i => i.ItemName == "purple elephant");

Read: Get the index of a given item using LINQ

阅读：使用 LINQ 获取给定项目的索引

回答by msam

You can loop with findIndexgiving an index

您可以使用findIndex循环给出索引

string[] arr = { "abc", "asd", "def", "abc", "lmn", "wer" };
int index = -1;
do
{
    index = Array.IndexOf(arr, "abc", index + 1);
    System.Console.WriteLine(index);
} while (-1 != index);

回答by stukselbax

No, there is not. But you can write your own extension method.

不，那里没有。但是您可以编写自己的扩展方法。

public static int[] FindAllIndexOf<T>(this T[] a, Predicate<T> match)
{
   T[] subArray = Array.FindAll<T>(a, match);
   return (from T item in subArray select Array.IndexOf(a, item)).ToArray();
}

and then, for your array, call it.

然后，对于您的数组，调用它。

回答by Rocket

Searches for an element that matches the conditions defined by the specified predicate, and returns all the zero-based index of the occurrence within the entire System.Array.

搜索与指定谓词定义的条件匹配的元素，并返回整个 System.Array 中出现的所有从零开始的索引。

public static int[] FindAllIndex<T>(this T[] array, Predicate<T> match)
{
    return array.Select((value, index) => match(value) ? index : -1)
            .Where(index => index != -1).ToArray();
}

回答by Sirwan Esfehani

I'm aware that the question is answered already, this is just another way of doing it. note that I used ArrayListinstead of int[]

我知道这个问题已经回答了，这只是另一种方式。请注意，我使用ArrayList而不是int[]

// required using directives
using System;
using System.Collections;

String      inputString = "The lazy fox couldn't jump, poor fox!";
ArrayList   locations   =  new ArrayList();      // array for found indexes
string[] lineArray = inputString.Split(' ');     // inputString to array of strings separated by spaces

int tempInt = 0;
foreach (string element in lineArray)
{
     if (element == "fox")
     {
         locations.Add(tempInt);   // tempInt will be the index of current found index and added to Arraylist for further processing 
     }
 tempInt++;
}

回答by Henrik Larsen

I've used Nikhil Agrawal's answer to create the following related method, which may be useful.

我已经使用 Nikhil Agrawal 的回答创建了以下相关方法，这可能很有用。

public static List<int> FindAllIndexOf<T>(List<T> values, List<T> matches)
    {
        // Initialize list
        List<int> index = new List<int>();

        // For each value in matches get the index and add to the list with indexes
        foreach (var match in matches)
        {
            // Find matches 
            index.AddRange(values.Select((b, i) => Equals(b, match) ? i : -1).Where(i => i != -1).ToList());

        }

        return index;
    }

Which takes a list with values and a list with values that are to be matched. It returns a list of integers with the index of the matches.

它需要一个包含值的列表和一个包含要匹配的值的列表。它返回一个带有匹配索引的整数列表。

回答by Fatih Kaan A?IKG?Z

You can solve this problem by creating only 2 integer variables. More power to you!

您可以通过仅创建 2 个整数变量来解决此问题。给你更多的力量！

string[] seasons= { "Fall","Spring", "Summer", "Fall", "Fall", "Winter"};

int i = 0;

int IndexOfFallInArray = 0;

int[] IndexesOfFall= new int[seasons.Length];

foreach (var item in seasons)
{
    if (item == "Fall")
        {
            IndexesOfFall[i] = IndexOfFallInArray;
            i++;
        }
        IndexOfFallInArray++;
}

回答by Furkan ?ztürk

I know this is an old post, but you can try the following,

我知道这是一个旧帖子，但您可以尝试以下操作，

string[] cars = {"Volvo", "BMW", "Volvo", "Mazda","BMW","BMW"};
var res = Enumerable.Range(0, cars.Length).Where(i => cars[i] == "BMW").ToList();

returns {1,4,5}as a list

以列表形式返回{1,4,5}