如何访问 TypeScript 中的静态方法
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How to access static methods in TypeScript
提问by Kal_Torak
I'm trying to do this, but it's not working like I'd expect.
我正在尝试这样做，但它并没有像我期望的那样工作。
(I'm using the AMD option)
（我正在使用 AMD 选项）
//logger.ts
export class Logger {
static log(message: string) {
//do stuff
}
}
//main.ts
import logger = module('services/logger');
logger.log("test"); //The property 'log' does not exist on value of type '"logger"'
logger.Logger.log(); //works
How do you do logger.log()?
你怎么做 logger.log()？
回答by Dimitris
You can import classes directly, which allows you to have the usage you want.
您可以直接导入类，这样您就可以拥有所需的用法。
// usage
import { Logger } from 'path/logger.ts'
Logger.Log();
And the definition stays the same.
并且定义保持不变。
// path/logger.ts
export class Logger {
static Log() {
...
}
}
回答by Jude Fisher
This answer was correct at time of posting. It is now deprecated. See Dimitris' answerfor a better current solution.
这个答案在发布时是正确的。现在已弃用。有关更好的当前解决方案，请参阅Dimitris 的回答。
Using a class, you can't. You're always going to have to call {module}.{class}.{function}
使用类，你不能。你总是要打电话{module}.{class}.{function}
But you can drop the class altogether and just call {module}.{function}:
但是你可以完全放弃课程，只需调用{module}.{function}：
// services/logger.ts
export function log(message:string){
// do stuff
}
//main.ts
import logger = module('services/logger');
logger.log("test"); // Should work
