PHP 提交选择
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/16244228/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
PHP Submit on Select
提问by Danny Boy
I am trying to not have a submit button, is there any way that the form can submit when the user selects a value?
我试图没有提交按钮，当用户选择一个值时，有什么方法可以提交表单吗？
<form method="post" action="<?php echo $_SERVER['PHP_SELF'] ?>" >
<table class="form">
<select name="category" class="formfield" id="category">
<option value="-1"> Category </option>
<?php
$sql_contry = "SELECT * FROM category";
$rs_c = mysql_query($sql_contry);
while ($row_c = mysql_fetch_array($rs_c)) {
echo '<option value="'.$row_c['category'].'">'.$row_c['category'].'</option>';
}
?>
</select>
</table>
</form>
回答by TheEwook
Here an example
这里有一个例子
<form>
<select name='myfield' onchange='this.form.submit()'>
<option selected>Milk</option>
<option>Coffee</option>
<option>Tea</option>
</select>
<noscript><input type="submit" value="Submit"></noscript>
</form>
Using noscript tag it allows browsers that are not JavaScript-enabled to still function.
使用 noscript 标签，它允许未启用 JavaScript 的浏览器仍然运行。
回答by Adidi
Yes - use javascript:
是 - 使用 javascript：
Html:
网址：
<form id="frm">
<select onchange="onSelectChange();">
<option>1</option>
<option>1</option>
<select>
</form>
js:
js：
function onSelectChange(){
document.getElementById('frm').submit();
}
回答by web2students.com
Just change code as below, I haven't check code so there may be some error like capital/small letter I am not sure like, it's submit() or Submit() and so on..
只需更改代码如下，我没有检查代码所以可能会有一些错误，比如大写/小写字母我不确定，是 submit() 或 Submit() 等等..
<script language="javascript">
function submitForm(){
var val = document.myform.category.value;
if(val!=-1){
document.myform.submit();
}
}
</script>
<form method="post" name="myform" action="<?php echo $_SERVER['PHP_SELF'] ?>" >
<table class="form">
<select name="category" class="formfield" id="category" onchange="submitForm();">
<option value="-1"> Category </option>
<?php
$sql_contry = "SELECT * FROM category";
$rs_c = mysql_query($sql_contry);
while ($row_c = mysql_fetch_array($rs_c)) {
echo '<option value="'.$row_c['category'].'">'.$row_c['category'].'</option>';
}
?>
</select>
</table>
</form>
回答by Abid Shah
<form action="product.php" method="POST">
<select onchange="this.form.submit();" name="prod">
<option value="">Select product</option>
<option value="1">abc</option>
<option value="2">def</option>
<option value="3">ghi</option>
<option value="4">jkl</option>
<option value="5">mno</option>
</select>
