string Groovy：从给定的字符集生成随机字符串
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Groovy: Generate random string from given character set
提问by Robert Strauch
Using Groovy, I'd like to generate a random sequence of characters from a given regular expression.
使用 Groovy，我想从给定的正则表达式生成随机字符序列。
- Allowed charaters are:
[A-Z0-9] - Length of generated sequence: 9
- 允许的字符是：
[A-Z0-9] - 生成序列的长度：9
Example: A586FT3HS
例子： A586FT3HS
However, I can't find any code snippet which would help me. If using regular expressions is too complicated, I'll be fine defining the allowed set of characters manually.
但是，我找不到任何对我有帮助的代码片段。如果使用正则表达式太复杂，我可以手动定义允许的字符集。
回答by tim_yates
If you don't want to use apache commons, or aren't using Grails, an alternative is:
如果您不想使用 apache commons，或者不使用 Grails，另一种方法是：
def generator = { String alphabet, int n ->
new Random().with {
(1..n).collect { alphabet[ nextInt( alphabet.length() ) ] }.join()
}
}
generator( (('A'..'Z')+('0'..'9')).join(), 9 )
but again, you'll need to make your alphabetyourself... I don't know of anything which can parse a regular expression and extract out an alphabet of passing characters...
但同样，你需要alphabet自己做......我不知道有什么可以解析正则表达式并提取出传递字符的字母表......
回答by Dónal
import org.apache.commons.lang.RandomStringUtils
String charset = (('A'..'Z') + ('0'..'9')).join()
Integer length = 9
String randomString = RandomStringUtils.random(length, charset.toCharArray())
The imported class RandomStringUtilsis already on the Grails classpath, so you shouldn't need to add anything to the classpath if you're writing a Grails app.
导入的类RandomStringUtils已经在 Grails 类路径中，因此如果您正在编写 Grails 应用程序，则不需要向类路径添加任何内容。
Update
更新
If you only want alphanumeric characters to be included in the String you can replace the above with
如果您只想在字符串中包含字母数字字符，您可以将上面的替换为
String randomString = org.apache.commons.lang.RandomStringUtils.random(9, true, true)
回答by user3215161
For SoupUI users:
对于 SoupUI 用户：
def generator = { String alphabet, int n ->
new Random().with {
(1..n).collect { alphabet[ nextInt( alphabet.length() ) ] }.join()
}
}
randomValue = generator( (('A'..'Z')+('0'..'9')+('a'..'z')).join(), 15 )
testRunner.getTestCase().setPropertyValue("randomNumber", randomValue);
回答by vkrams
Here is a single line command/statement to generate random text string
这是生成随机文本字符串的单行命令/语句
print new Random().with {(1..9).collect {(('a'..'z')).join()[ nextInt((('a'..'z')).join().length())]}.join()}
or
或者
def randText = print new Random().with {(1..9).collect {(('a'..'z')).join()[ nextInt((('a'..'z')).join().length())]}.join()}
回答by Sjoerd
回答by Abdelsalam Shahlol
This code is pure Groovy I found on the web:
这段代码是我在网上找到的纯 Groovy：
def key
def giveMeKey(){
String alphabet = (('A'..'N')+('P'..'Z')+('a'..'k')+('m'..'z')+('2'..'9')).join()
def length = 6
key = new Random().with {
(1..length).collect { alphabet[ nextInt( alphabet.length() ) ] }.join()
}
return key
}
The return string is good enough for local use:
返回字符串足以在本地使用：
BFx9PU
MkbRaE
FKvupt
gEwjby
Gk2kK6
uJmzLB
WRJGKL
RnSUQT
