在 Java 中读取多个文件
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Read Multiple Files In Java
提问by user951487
I want to read multiple files into Java at once. File names are like:
我想一次将多个文件读入 Java。文件名类似于：
- nnnnn_UM2012.txt
- ghkjdf_UM2045.txt
- erey_UM2189.txt
- ....
- nnnnn_UM2012.txt
- ghkjdf_UM2045.txt
- erey_UM2189.txt
- ....
There are over 1,000 files and I do not want to write all files names in Java one by one, using code similar to the following one:
有1000多个文件，我不想把所有文件名用Java一一写出来，使用类似于以下的代码：
String fileNames = {"nnnnn_UM2012.txt","ghkjdf_UM2045.txt","erey_UM2189.txt", …}
Maybe the filenames should be read in reverse order. How can I do that?
也许应该以相反的顺序读取文件名。我怎样才能做到这一点？
回答by Mike Kwan
回答by Steve McLeod
To get all files in a folder (sub-folders are included in the list of files):
要获取文件夹中的所有文件（子文件夹包含在文件列表中）：
// get all files in the folder
final File folder = new File(".");
final List<File> fileList = Arrays.asList(folder.listFiles());
To get all files in a folder, excluding sub-folders:
要获取文件夹中的所有文件，不包括子文件夹：
// get all files in the folder excluding sub-folders
final File folder = new File(".");
final List<File> fileList = Arrays.asList(folder.listFiles(new FileFilter() {
public boolean accept(File pathname) {
return pathname.isFile();
}
}));
To sort the list of files into reverse case-sensitive order:
要将文件列表排序为区分大小写的反向顺序：
// sort the files into reverse order
Collections.sort(fileList, new Comparator<File>() {
public int compare(File o1, File o2) {
return o2.getName().compareTo(o1.getName());
}
});
To sort the list of files into reverse case-insensitive order:
要将文件列表排序为不区分大小写的反向顺序：
// sort the files into reverse order ignoring case
Collections.sort(fileList, new Comparator<File>() {
public int compare(File o1, File o2) {
return o2.getName().compareToIgnoreCase(o1.getName());
}
});
回答by Adithya
You can follow the below approach if all the files are in a single directory.
Get a reference to the directory by providing its fully qualified path and then use the list()function get all the file names into a Stringarray inside the directory.
如果所有文件都在一个目录中，您可以遵循以下方法。通过提供目录的完全限定路径来获取对目录的引用，然后使用list()函数将所有文件名放入String目录内的数组中。
After this step you can sort the files according to the way you want (For e.g. by its name,length,etc..).
在这一步之后，您可以根据您想要的方式（例如，按名称、长度等）对文件进行排序。
回答by Manuel Leduc
File rep = new File("path to rep");
File[] list = rep.listFiles();
ArrayList<String> filenames = new ArrayList<String>();
for ( int i = 0; i < list.length; i++) {
filenames.add(list[i].getName());
}
I guess it can be a solution to your problem.
我想它可以解决您的问题。
