将变量从一个 shell 脚本导出到 bash 中的另一个脚本
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Exporting variable from one shell script to another script in bash
提问by vikeng21
I am a newbie in Shell Scripting and i am trying to export a variable from child script to a parent script.below is the code and unfortunately its not working. not sure what is the issue. below is the code.
我是 Shell Scripting 的新手，我正在尝试将变量从子脚本导出到父脚本。下面是代码，不幸的是它不起作用。不知道是什么问题。下面是代码。
I have a script set-vars1.sh code is as below
我有一个脚本 set-vars1.sh 代码如下
#!/bin/bash
line_write="R"
FLAG=''
if [[ $line_write > " " && $line_write == "R" ]]
then
echo "Exporting"
export FLAG=Y
#export $FLAG;
elif [[ $line_write > " " && $line_write== "N" ]]
then
export FLAG=N
fi
EXIT_STATUS=-1
exit $EXIT_STATUS
I am trying to call this from set-vars2.sh the code is as below
我试图从 set-vars2.sh 调用它，代码如下
#!/bin/bash
./set-vars1.sh
echo $FLAG
When i try to run set-vars2.sh i am not able to echo the value of FLAG and its always blank.
当我尝试运行 set-vars2.sh 时，我无法回应 FLAG 的值并且它始终为空白。
Can you please let me know what is wrong here and how i can correct the same. been breaking my head a long time on this. so any help would be hugely helpful
你能告诉我这里有什么问题吗，我该如何纠正。很长一段时间我都在为此伤脑筋。所以任何帮助都会非常有帮助
回答by Jahid
use source:
使用source：
source ./set-vars1.sh
Or:
或者：
. ./set-vars1.sh
#The first . is intentional
