java 如何下载受热链接保护的图片？
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How to download hotlink protected images?
提问by Yatendra Goel
I want to download images from other websites that are hotlink protected. I don't want to link those images to my website. I just wanted to download them.
我想从其他受热链接保护的网站下载图像。我不想将这些图像链接到我的网站。我只是想下载它们。
回答by Aziz
The usual hotlink-protection methodchecks if the "Referrer" HTTP Headermatches the domain name of the original website.
在通常的热链保护方法检查是否“推荐人” HTTP标头相匹配的原始网站的域名。
You can easily bypass that by setting that header manually to point to a page in the website.
您可以通过手动设置该标题以指向网站中的页面来轻松绕过它。
回答by Gattster
You need to pass the referrer http header. You can do this with wget on most unix systems as follows:
您需要传递引用 http 标头。您可以在大多数 unix 系统上使用 wget 执行此操作，如下所示：
wget --referer=http://www.google.com/ http://www.google.com/intl/en_ALL/images/logo.gif
Here a raw way to do it so you see exactly what is going on:
这是一种原始的方法，因此您可以准确了解正在发生的事情：
telnet google.com 80
GET /intl/en_ALL/images/logo.gif HTTP/1.1
REFERER: http://www.google.com/
HOST: www.google.com
回答by Birdman
You can download hotlink protected images by using the following code:
您可以使用以下代码下载受热链接保护的图像：
URL url = new URL("http://www.somesite.com/picture.jpg");
URLConnection urlCon = url.openConnection();
urlConn.setRequestProperty("Referer", "http://www.somesite.com");
urlConn.connect();
InputStream urlStream = urlCon.getInputStream();
Image image = ImageIO.read(urlStream);
回答by Dan Ross
The Postman extension for Chrome lets you make custom http requests. I found a hotlink-blocked image, copied it's url and entered it into Postman to GET it.
Chrome 的 Postman 扩展程序可让您自定义 http 请求。我找到了一个阻止热链接的图像，复制了它的 url 并将其输入 Postman 以获取它。
