Javascript 为什么我会收到一条错误消息，指出 .replace 不是函数？
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Why do I get an error message that .replace is not a function?
提问by anleon
I have this function:
我有这个功能：
function countLitreKgSums(cProductIds){
var cLitreKgSums = new Array();
var cWeek = 0;
for(i=0;i<cProductIds.length;i++){
var cLitreKgSum = 0;
$("#plan_table td[class='week']").each(function(){
cWeek = $(this).html();
var cLitreKgValue = $("input[name*='plan_table_week" + cWeek + "_prod" + cProductIds[i] + "_']").val();
if (cLitreKgValue == "") {
cLitreKgValue = 0;
}
cLitreKgValue = cLitreKgValue.replace(/,/g, '.').replace(/[^\d\.]/g, '').replace(/\s/g, '');
cLitreKgValue = parseFloat(cLitreKgValue);
cLitreKgSum += cLitreKgValue;
});
cLitreKgSum = Math.round(cLitreKgSum * 100) / 100;
cLitreKgSums[i] = cLitreKgSum;
}
return cLitreKgSums;
//console.log(cLitreKgSums);
}
I get error message that .replace is not a function but in other functions it works as it should. What is the difference?
我收到错误消息，指出 .replace 不是一个函数，但在其他函数中它可以正常工作。有什么不同？
回答by Andrzej Doyle
cLitreKgValuemight be a number at the point where you try to call replaceon it, not a string. In which case, the error is correct - numbers don't have a replacemethod.
cLitreKgValue可能是您尝试调用replace它时的数字，而不是字符串。在这种情况下，错误是正确的 - 数字没有replace方法。
回答by Jonathon Faust
Change this:
改变这个：
cLitreKgValue.replace(/,/g, '.')
to
到
("" + cLitreKgValue).replace(/,/g, '.')
回答by Joao B
you can use the function String()
i.e.; String(cLitreKgValue).replace ....
String function:
http://www.w3schools.com/jsref/jsref_string.asp
您可以使用函数 String()
即；String(cLitreKgValue).replace ....
字符串函数：http:
//www.w3schools.com/jsref/jsref_string.asp
回答by Nick Craver
While the other answers work (and are correct, numbers don't have .replace(), it's a Stringmethod), I think an overall structure change is better, like this:
虽然其他答案有效（并且是正确的，数字没有.replace()，这是一种String方法），但我认为整体结构变化更好，如下所示：
$("#plan_table td[class='week']").each(function(){
cWeek = $(this).html();
var cLitreKgValue = $("input[name*='plan_table_week" + cWeek + "_prod" + cProductIds[i] + "_']").val();
if (cLitreKgValue !== "") {
cLitreKgValue = cLitreKgValue.replace(/,/g, '.').replace(/[^\d\.]/g, '').replace(/\s/g, '');
cLitreKgSum += parseFloat(cLitreKgValue);
}
});
There's no reason to do all that work when you know it's 0and doesn't affect the result, so if ""means 0and anything += 0has no net effect, just skip it :)
当你知道它0不会影响结果时，没有理由做所有这些工作，所以如果""意味着0并且anything += 0没有实际影响，只需跳过它:)
