`System.out.println()` 方法调用上的 Java 语法错误
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/9763584/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Java syntax error on `System.out.println()` method call
提问by Vladislav Bogdanov
I'm sorry for the extremely short question, but i don't even know why i have this error:
对于这个极短的问题，我很抱歉，但我什至不知道为什么会出现此错误：
Syntax error on token "println", = expected after this token
Syntax error on token "println", = expected after this token
In this code:
在这段代码中：
static long start = System.currentTimeMillis();
public void testSort5() {
Random random = new Random();
int number;
int[] arr = new int[1000];
for (int counter = 1; counter < 1000; counter++) {
number = 1 + random.nextInt(1000);
arr[counter] = number;
}
int[] actual = MergeSort.sort(arr);
}
long end = System.currentTimeMillis();
System.out.println("Execution time was " + (end - start) + " ms.");
回答by Oliver Charlesworth
You have statements outsideyour method body.
您在方法主体之外有语句。
回答by jefflunt
Your last two lines:
你的最后两行：
long end ...
System.out.println...
Appear to be outside of any method. You can't just run code outside of a method, unlessit's a variable/constant declaration, a class declaration, or other special situations. This is why you get the syntax error on the System.out.println(...)call, but not on the static long start...or long end...declarations.
似乎在任何方法之外。您不能只在方法之外运行代码，除非它是变量/常量声明、类声明或其他特殊情况。这就是为什么您会在System.out.println(...)调用中出现语法错误，而在static long start...orlong end...声明中却没有。
回答by Java42
As the others said, but to fix, do the following:
正如其他人所说，但要修复，请执行以下操作：
change
改变
long end = System.currentTimeMillis();
System.out.println("Execution time was " + (end - start) + " ms.");
to
到
static {
Runtime.getRuntime().addShutdownHook(new Thread() {
public void run(){
long end = System.currentTimeMillis();
System.out.println("Execution time was " + (end - start) + " ms.");
}});
}
回答by KingFeming
You will get Syntax error on token when you have wrote all your java codes in the class itself without defining a method.
当您在类本身中编写所有 java 代码而没有定义方法时，您将在令牌上收到语法错误。
Solution for this type of issue is, simply create a method/ main method under the class and then code there..
此类问题的解决方案是，只需在类下创建一个方法/主方法，然后在那里编码..
This way will resolve the problem too.
这种方式也能解决问题。
