Android 无法启动服务意图

Question

提问by Vinay

I have a service class. I have exported this class to jar and I have embed the jar in my client app.

我有一个服务类。我已将此类导出到 jar 并将该 jar 嵌入到我的客户端应用程序中。

When needed, I call the service class. When I try to do this, I get the following error:

需要时，我会调用服务类。当我尝试这样做时，我收到以下错误：

Unable to start service Intent {comp={com.sample.service/com.sample.service.serviceClass}} : not found

I have other class apart from the service class, which I am able to access (create object of that class) which are inside the same jar.

除了服务类之外，我还有其他类，我可以访问（创建该类的对象），它们位于同一个 jar 中。

I feel I have missed out some thing in my configuration or manifest or so.

我觉得我在配置或清单中遗漏了一些东西。

Please help me identifying the same. My code is below:

请帮我识别相同的。我的代码如下：

public void onCreate(Bundle savedInstanceState) {    
      super.onCreate(savedInstanceState);  
      Intent intent = new Intent () ;  
      intent.setClassName("com.sample.service" ,"com.sample.service.serviceClass") ;  
      this.startService(intent) ; // when I call this line I get the message...  
      // binding other process continue  here   
}

Client manifest.xml

客户端清单.xml

<service android:name="com.sample.service.serviceClass"  
            android:exported="true" android:label="@string/app_name" 
            android:process=":remote">
   <intent-filter><action android:name="com.sample.service.serviceClass"></action>
   </intent-filter>
</service>

Thanks in advance,
Vinay

提前致谢，
维奈

Answer 1

采纳答案by CommonsWare

First, you do not need android:process=":remote", so please remove it, since all it will do is take up extra RAM for no benefit.

首先，您不需要android:process=":remote"，所以请删除它，因为它只会占用额外的 RAM 而没有任何好处。

Second, since the <service>element contains an action string, use it:

其次，由于<service>元素包含一个动作字符串，请使用它：

public void onCreate(Bundle savedInstanceState) {    
      super.onCreate(savedInstanceState);  
      Intent intent=new Intent("com.sample.service.serviceClass");  
      this.startService(intent);
}

Answer 2

回答by Blundell

For anyone else coming across this thread I had this issue and was pulling my hair out. I had the service declaration OUTSIDE of the '< application>' end tag DUH!

对于遇到此线程的其他人，我遇到了这个问题并且正在拔头发。 我有“<应用程序>”结束标签的服务声明 DUH！

RIGHT:

对：

<manifest xmlns:android="http://schemas.android.com/apk/res/android"
  ...>
...
<application android:icon="@drawable/icon" android:label="@string/app_name">
    <activity ...>
        ...
    </activity>    

    <service android:name=".Service"/>

    <receiver android:name=".Receiver">
        <intent-filter>
            ...
        </intent-filter>
    </receiver>        
</application>

<uses-permission android:name="..." />

WRONG but still compiles without errors:

错误但仍然编译没有错误：

<manifest xmlns:android="http://schemas.android.com/apk/res/android"
  ...>
...
<application android:icon="@drawable/icon" android:label="@string/app_name">
    <activity ...>
        ...
    </activity>

</application>

    <service android:name=".Service"/>

    <receiver android:name=".Receiver">
        <intent-filter>
            ...
        </intent-filter>
    </receiver>        

<uses-permission android:name="..." />

Answer 3

回答by Jianhong

1) check if service declaration in manifest is nested in application tag

1) 检查清单中的服务声明是否嵌套在应用程序标签中

<application>
    <service android:name="" />
</application>

2) check if your service.javais in the same package or diff package as the activity

2）检查您service.java是否与活动在同一包或差异包中

<application>
    <!-- service.java exists in diff package -->
    <service android:name="com.package.helper.service" /> 
</application>

<application>
    <!-- service.java exists in same package -->
    <service android:name=".service" /> 
</application>

Answer 4

回答by sataniccrow

I hope I can help someone with this info as well: I moved my service class into another package and I fixed the references. The project was perfectly fine, BUT the service class could not be found by the activity.

我希望我也可以帮助提供此信息的人：我将我的服务类移到另一个包中并修复了引用。该项目非常好，但活动找不到服务类。

By watching the log in logcat I noticed the warning about the issue: the activity could not find the service class, but the funny thing was that the package was incorrect, it contained a "/" char. The compiler was looking for

通过观察 logcat 中的登录，我注意到有关该问题的警告：活动找不到服务类，但有趣的是包不正确，它包含一个“/”字符。编译器正在寻找

com.something./service.MyService

instead of

代替

com.something.service.MyService

I moved the service class out from the package and back in and everything worked just fine.

我将服务类从包中移出并移回，一切正常。

Answer 5

回答by marisxanis

I've found the same problem. I lost almost a day trying to start a service from OnClickListenermethod - outside the onCreateand after 1 day, I still failed!!!! Very frustrating! I was looking at the sample example RemoteServiceController. Theirs works, but my implementation does not work!

我发现了同样的问题。我花了将近一天的时间尝试从OnClickListener方法启动服务-onCreate在 1 天之后，我仍然失败了！！！！非常令人沮丧！我正在查看示例示例RemoteServiceController。他们的工作，但我的实施不起作用！

The only way that was working for me, was from inside onCreatemethod. None of the other variants worked and believe me I've tried them all.

对我有用的唯一方法是从内部onCreate方法。其他变体都没有工作，相信我，我已经尝试过所有这些变体。

Conclusion:

结论：

If you put your service class in different package than the mainActivity, I'll get all kind of errors
Also the one "/" couldn't find path to the service, tried starting with Intent(package,className)and nothing , also other type of Intent starting
I moved the service class in the same package of the activity Final form that works

Hopefully this helps someone by defining the listerners onClickinside the onCreatemethod like this:

public void onCreate() {
//some code......
    Button btnStartSrv  = (Button)findViewById(R.id.btnStartService);
    Button btnStopSrv  = (Button)findViewById(R.id.btnStopService);

    btnStartSrv.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            startService(new Intent("RM_SRV_AIDL"));
        }
    });

    btnStopSrv.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            stopService(new Intent("RM_SRV_AIDL"));
        }
    });

} // end onCreate

如果您将服务类放在与 mainActivity 不同的包中，我会收到各种错误
还有一个“/”找不到服务的路径，尝试从Intent(package,className)什么都没有开始，还有其他类型的 Intent 开始
我将服务类移动到有效的活动最终表单的同一个包中

希望这可以通过onClick在onCreate方法中定义侦听器来帮助某人，如下所示：

public void onCreate() {
//some code......
    Button btnStartSrv  = (Button)findViewById(R.id.btnStartService);
    Button btnStopSrv  = (Button)findViewById(R.id.btnStopService);

    btnStartSrv.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            startService(new Intent("RM_SRV_AIDL"));
        }
    });

    btnStopSrv.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            stopService(new Intent("RM_SRV_AIDL"));
        }
    });

} // end onCreate

Also very important for the Manifest file, be sure that service is child of application:

对于 Manifest 文件也非常重要，请确保服务是应用程序的子项：

<application ... >
    <activity ... >
     ...
    </activity>
    <service
        android:name="com.mainActivity.MyRemoteGPSService"
        android:label="GPSService"
        android:process=":remote">

        <intent-filter>
             <action android:name="RM_SRV_AIDL" />
        </intent-filter>
    </service>
</application>

Answer 6

回答by ranbuch

In my case the 1 MB maximum cap for data transport by Intent. I'll just use Cache or Storage.

在我的情况下，Intent 数据传输的最大上限为 1 MB。我只会使用缓存或存储。

Android 无法启动服务意图

提问by Vinay

采纳答案by CommonsWare

回答by Blundell

回答by Jianhong

回答by sataniccrow

回答by marisxanis

回答by ranbuch

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标签

Android 无法启动服务意图

提问by Vinay

采纳答案by CommonsWare

回答by Blundell

回答by Jianhong

回答by sataniccrow

回答by marisxanis

回答by ranbuch

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