javascript 如何grep包含在javascript或jquery中的JSON数组
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How to grep the JSON array contains in javascript or jquery
提问by Ugesh Gali
var dummyArray = [{
"fname": "gali",
"lname": "doe"
}, {
"fname": "john",
"lname": "danny"
}, {
"fname": "joe",
"lname": "dawns"
}, {
"fname": "liji",
"lname": "hawk"
}]
dummyArray = j$.grep(dummyArray , function(dt) {
return (dt.fname== 'j');
});
How to query the "fname" which contains letter "j" using grep function.
如何使用 grep 函数查询包含字母“j”的“fname”。
回答by Alnitak
Using the ES5 standard function Array.filterto only return the elements matching the predicate:
使用 ES5 标准函数Array.filter只返回匹配谓词的元素：
Starting with "j"
以“j”开头
var j = dummyArray.filter(function(o) {
return o.fname.charAt(0) === 'j';
});
or, containing "j"
或者，包含“j”
var j = dummyArray.filter(function(o) {
return o.fname.indexOf('j') >= 0;
});
回答by VisioN
You can use indexOf:
您可以使用indexOf：
dummyArray = $.grep(dummyArray, function(dt) {
return dt.fname.indexOf("j") != -1;
});
回答by elclanrs
You can do this with vanilla js like so:
你可以像这样使用 vanilla js 来做到这一点：
dummyArray = (function(){
var result = [];
for (var i=0, l=dummyArray.length; i<l; i++)
if (/j/.test(dummyArray[i].fname))
result.push(dummyArray[i]);
return result;
}());
You can easily test stuff by changing the regex, for example you could test for names that startby jinstead of containwith /^j/
您可以通过更改正则表达式，例如，你可以测试名称容易测试的东西，开始用j，而不是包含有/^j/
回答by Dhanasekar
You can use Index Of function:
您可以使用 Index Of 功能：
dummyArray = $.grep(dummyArray, function(dt) {
return dt.fname.indexOf("j") != -1;
});
//to be case-insensitive, use :
dummyArray = $.grep(dummyArray, function(dt) {
return dt.fname.toLowerCase().indexOf("j") != -1;
});
Fiddle: http://jsfiddle.net/kYXPa/
