bash 如何从失败的命令返回退出代码 0
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/36130299/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to return exit code 0 from a failed command
提问by meso_2600
I would like to return exit code "0" from a failed command. Is there any easier way of doing this, rather than:
我想从失败的命令中返回退出代码“0”。有没有更简单的方法来做到这一点，而不是：
function a() {
ls aaaaa 2>&1;
}
if ! $(a); then
return 0
else
return 5
fi
回答by Michael Daffin
Simply append return 0to the function to force a function to always exit successful.
只需附加return 0到函数即可强制函数始终成功退出。
function a() {
ls aaaaa 2>&1
return 0
}
a
echo $? # prints 0
If you wish to do it inline for any reason you can append || trueto the command:
如果您出于任何原因希望内联执行，您可以附加|| true到命令：
ls aaaaa 2>&1 || true
echo $? # prints 0
If you wish to invert the exit status simple prepend the command with !
如果您希望简单地反转退出状态，请在命令前加上 !
! ls aaaaa 2>&1
echo $? # prints 0
! ls /etc/resolv.conf 2>&1
echo $? # prints 1
Also if you state what you are trying to achieve overall we might be able to guide you to better answers.
此外，如果您说明您总体上想要达到的目标，我们或许可以指导您找到更好的答案。
