如何使用带有 WebMatrix 的 C#.net 网页访问单个 XML 元素的值？
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How can I access a single XML element's value using C#.net web-pages with WebMatrix?
提问by VoidKing
I've looked at a lot of resources, done a lot of research, and tried many "best-guesses" to access a single element at a time using WebMatrix with C#, web-pages, however nothing I am trying is getting through.
我查看了大量资源，进行了大量研究，并尝试了许多“最佳猜测”以使用 WebMatrix 和 C#、网页一次访问单个元素，但是我尝试的任何内容都没有通过。
Consider a simple xml document that looks like this:
考虑一个如下所示的简单 xml 文档：
<root>
<requisitionData>
<element1>I am element 1</element1>
<element2>I am element 2</element2>
</requisitionData>
</root>
I know I can use a foreach loop, like so:
我知道我可以使用 foreach 循环，如下所示：
@using System.Xml.Linq
XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));
foreach (XElement element in doc.Descendants("requisitionData"))
{
@element.Value
}
And that, of course, works fine. But what if I simply wanted to store the single element, <element1>'s value in a string variable?
当然，这很好用。但是，如果我只是想将单个元素<element1>的值存储在字符串变量中呢？
I've looked here (link below), but I can't make heads or tails of this code (it barely even looks like C# to me, but then again, I'm so new to parsing XML...):
我看过这里（下面的链接），但我无法理解这段代码的正面或反面（对我来说，它甚至看起来都不像 C#，但话说回来，我对解析 XML 还是很陌生……）：
I've also checked here: How to Get XML Node from XDocument
我也在这里检查过：How to Get XML Node from XDocument
But the code shown makes no sense to me here either. I keep thinking there must be a simpler way to do this, hopefully without learning a whole new querying approach.
但是这里显示的代码对我来说也没有意义。我一直认为必须有一种更简单的方法来做到这一点，希望无需学习全新的查询方法。
---------------------------------THINGS I'VE TRIED---------------------------------
---------------------------------我尝试过的事情------------ ---------------------
XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));
string element = doc.Descendants("requisitionData").Descendants("element1").Value;
Error I receive:"missing using directive or assembly reference
我收到错误：“缺少使用指令或程序集引用
XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));
XElement element = doc.Descendants("element1");
string val = element.Value;
Error I receive:Cannot implicitly convert type 'System.Collections.Generic.IEnumerable' to 'System.Xml.Linq.XElement'. An explicit conversion exists (are you missing a cast?)
我收到的错误：无法将类型“System.Collections.Generic.IEnumerable”隐式转换为“System.Xml.Linq.XElement”。存在显式转换（您是否缺少演员表？）
I have, indeed, tried other things, but I get pretty much the same errors as shown above. Am I making this harder than it is, or am I oversimplifying it?
我确实尝试过其他事情，但我得到了与上面显示的几乎相同的错误。我是让这件事变得比现在更难，还是我过于简单化了？
-------------------------UPDATE------------------------------
- - - - - - - - - - - - -更新 - - - - - - - - - - - - ------
I was able to get this to work:
我能够让它工作：
string element = doc.Element("root").Element("requisitionData").Element("element1").Value;
@element
However, one thing that concerns me about this approach is that .Elementselects the 'first' match, so in an xml document that looks like this:
但是，我对这种方法担心的一件事是.Element选择“第一个”匹配项，因此在如下所示的 xml 文档中：
<root>
<requisitionData>
<element1>I am element 1</element1>
<element2>I am element 2</element2>
</requisitionData>
<requisitionData>
<element1>I am element 1</element1>
<element2>I am element 2</element2>
</requisitionData>
</root>
How could I access the second occurrence of <element1>?
我如何访问第二次出现的<element1>？
采纳答案by Darin Dimitrov
@using System.Xml.Linq
XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));
foreach (XElement element in doc.Element("root").Element("requisitionData").Descendants())
{
string value = element.Value;
}
or with XPath:
或使用 XPath：
@using System.Xml.Linq
@using System.Xml.XPath
XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));
foreach (XElement element in doc.XPathSelectElement("//requisitionData").Descendants())
{
string value = element.Value;
}
UPDATE:
更新：
And if you wanted to select for example the second <element1>node from your updated example:
如果您想<element1>从更新的示例中选择例如第二个节点：
string value = doc.XPathSelectElement("//requisitionData[2]/element1").Value;
