Java数组返回最高数组索引
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Java arrays returning highest array index
提问by user3071909
I am supposed to write a program that finds the largest index in an unsorted array of integers.
我应该编写一个程序，在未排序的整数数组中找到最大的索引。
Use a method that takes an array of integers as a parameter. The method should search the array and return the index of the largest value.
使用将整数数组作为参数的方法。该方法应该搜索数组并返回最大值的索引。
So i wrote a program that returns the highest value, for example it returns 13 as the highest number instead of the index of 2. So how would i return the index instead of the highest number itself? If that is an easy fix, does the rest of my code look correct? Thanks!
所以我写了一个返回最高值的程序，例如它返回 13 作为最高数字而不是 2 的索引。那么我将如何返回索引而不是最高数字本身？如果这是一个简单的修复，我的其余代码看起来是否正确？谢谢！
public class LargestInteger
{
public static void main(String[] args)
{
int[] largeArray = {5,4,13,7,7,8,9,10,5};
System.out.println(findLargest(largeArray));
}
public static int findLargest(int array[])
{
int largest = array[0];
for(int i = 0; i < array.length; i++)
{
if(array[i] > largest)
largest = array[i];
}
return largest;
}
}
回答by Jason
You need to keep and store the largest index. Try this:
您需要保留和存储最大的索引。尝试这个：
public static int findLargest(int array[])
{
int largest = array[0];
int largestIndex = 0;
for(int i = 0; i < array.length; i++)
{
if(array[i] > largest) {
largest = array[i];
largestIndex =i;
}
}
return largestIndex;
}
回答by Arbiter
Create a forloop at the end of the method, and a variable like index. Search through the list and find if the variable matches, remembering to increment the indexvariable every time.
for在方法末尾创建一个循环，并创建一个变量，如index. 搜索列表并查找变量是否匹配，记住index每次都增加变量。
Example:
例子：
int index = 0;
for (int i : array)
{
if (i == largest)
{
break;
}
index++;
}
return index;
回答by msmolcic
You can add aditional method that gets largest number and an array then search for index of that number:
您可以添加获取最大数字和数组的附加方法，然后搜索该数字的索引：
public class LargestInteger
{
public static void main(String[] args)
{
int[] largeArray = {5,4,13,7,7,8,9,10,5};
System.out.println(indexOfLargest(largeArray, findLargest(largeArray)));
}
public static int findLargest(int array[])
{
int largest = array[0];
for(int i = 0; i < array.length; i++)
{
if(array[i] > largest)
largest = array[i];
}
return largest;
}
public static int indexOfLargest(int array[], int number)
{
for (int i = 0; i < array.length; i++) {
if (array[i] == number)
return i;
}
return -1;
}
}
回答by Rakesh KR
Can also done with,
也可以做到，
int[] largeArray = {5,4,13,7,7,8,9,10,5};
int largestElement = findLargest(largeArray);
int index = Arrays.asList(5,4,13,7,7,8,9,10,5).indexOf(largestElement);
回答by Gabriel
In java 8 you can do it simply:
在 java 8 中，你可以简单地做到：
To get the highest:
获得最高：
int[] largeArray = {5,4,13,7,7,8,9,10,5};
System.out.println(IntStream.of(largeArray).max().getAsInt());
result: 13
结果：13
And to sum them:
总结一下：
System.out.println(IntStream.of(largeArray).sum());
result: 68
结果：68
