Java 整数数组列表到字符串的转换
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Conversion of Integer Arraylist to string
提问by HymanAttack
I'm trying to convert the numbers of my Array list into Strings at point i. How do I do this so I can create substrings of my numbers?
我正在尝试将我的数组列表的数字转换为第 i 点的字符串。我该怎么做才能创建数字的子字符串？
ArrayList<Integer> numbers= new ArrayList<Integer>();
for( int i=0; i<=10; i++){
String numbersString[i] = String.valueOf(numbers[i]);
}
采纳答案by C.B.
If numbers[i]is of type Integeryou can just use its built in toString()method. However, as numbersis an ArrayList, you need to use numbers.get(i).
如果numbers[i]是类型，Integer您可以使用其内置toString()方法。然而，由于numbers是ArrayList，你需要使用numbers.get(i)。
String numbersString[i] = ...is invalid syntax. You have to declare your array outside the loop and then access it simply by numbersString[i] = ...inside the loop.
String numbersString[i] = ...是无效的语法。您必须在循环外声明数组，然后numbersString[i] = ...在循环内简单地访问它。
回答by Kartik
I would suggest something like this.
我会建议这样的事情。
StringBuilder sb = new StringBuilder();
for (Integer number : numbers) {
sb.append(number != null ? number.toString() : "");
}
System.out.println("The number string = " + sb.toString());
回答by Murillo Maia
Looking your code you need a input of ArrayList and output of String[].
查看您的代码，您需要 ArrayList 的输入和 String[] 的输出。
You can use Collections2 of Guava lib to transform to string and after parse to array.
您可以使用 Guava lib 的 Collections2 转换为字符串，然后解析为数组。
ArrayList<Integer> numbers = new ArrayList<Integer>();
Collection<String> transform = Collections2.transform(numbers, new Function<Integer, String>() {
@Override
@Nullable
public String apply(@Nullable Integer input) {
return input.toString();
}
});
final String[] array = transform.toArray(new String[transform.size()]);
