WPF - 如何使用模板创建图像按钮
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WPF - How to create image button with template
提问by Charlie
I am trying to create a button which has 3 images: a Normal image, a Pressed image and a Disabled image (I will use these for creating up/down arrow buttons).
我正在尝试创建一个包含 3 个图像的按钮：一个普通图像、一个按下图像和一个禁用图像（我将使用这些图像来创建向上/向下箭头按钮）。
I believe the correct approach would be to derive from Buttonand use a Templateand set triggers to change the image. I have 3 dependency properties, one for each image.
我相信正确的方法是从Button并使用 aTemplate和 set 触发器来更改图像。我有 3 个依赖属性，每个图像一个。
The images would be .png and have transparent backgrounds (as they are not rectangular).
图像将是 .png 并具有透明背景（因为它们不是矩形）。
I am looking for something like CBitmapButtonin MFC.
我正在寻找类似CBitmapButtonMFC 的东西。
回答by Charlie
You won't need dependency properties because you are inheriting from Button. You already have the IsPressedand IsEnabledproperties. In fact, this is all you need:
您不需要依赖属性，因为您是从Button. 您已经拥有IsPressed和IsEnabled属性。事实上，这就是你所需要的：
<Button x:Class="TestWpfApplication.ThreeStateImageButton"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
<Button.Template>
<ControlTemplate TargetType="{x:Type Button}">
<Grid>
<Image Name="Normal" Source="Resources/Normal.png"/>
<Image Name="Pressed" Source="Resources/Pressed.png" Visibility="Hidden"/>
<Image Name="Disabled" Source="Resources/Disabled.png" Visibility="Hidden"/>
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsPressed" Value="True">
<Setter TargetName="Normal" Property="Visibility" Value="Hidden"/>
<Setter TargetName="Pressed" Property="Visibility" Value="Visible"/>
</Trigger>
<Trigger Property="IsEnabled" Value="False">
<Setter TargetName="Normal" Property="Visibility" Value="Hidden"/>
<Setter TargetName="Disabled" Property="Visibility" Value="Visible"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Button.Template>
</Button>
With your UserControl code-behind file:
使用您的 UserControl 代码隐藏文件：
public partial class ThreeStateImageButton : Button
{
public ThreeStateImageButton()
{
InitializeComponent();
}
}
回答by PJUK
I have provided an alternative to this solution, its not quite as light weight but it offers much greater re-usability.
我提供了这个解决方案的替代方案，它的重量不是很轻，但它提供了更大的可重用性。
回答by tning
public static readonly DependencyProperty DefaultImageSourceProperty = DependencyProperty.Register("DefaultImageSource", typeof(ImageSource), typeof(PressedImageButton), new PropertyMetadata(null, new PropertyChangedCallback(DefaultImageSourceChangedCallback)));
public static readonly DependencyProperty PressedImageSourceProperty = DependencyProperty.Register("PressedImageSource", typeof(ImageSource), typeof(PressedImageButton), new PropertyMetadata(null, new PropertyChangedCallback(PressedImageSourceChangedCallback)));
public static readonly DependencyProperty ImageStretchProperty = DependencyProperty.Register("ImageStretch", typeof(Stretch), typeof(PressedImageButton), new PropertyMetadata(Stretch.None, new PropertyChangedCallback(ImageStretchChangedCallback)));
<ControlTemplate>
<Grid>
<Image Name="imgDefault" Source="{Binding Path=DefaultImageSource,ElementName=uc}" Stretch="{Binding Path=ImageStretch,ElementName=uc}"></Image>
<ContentPresenter Content="{TemplateBinding Property=ContentControl.Content}" />
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="Button.IsPressed" Value="True">
<Setter Property="Image.Source" TargetName="imgDefault" Value="{Binding Path=PressedImageSource,ElementName=uc}"></Setter>
<Setter Property="UIElement.Effect">
<Setter.Value>
<DropShadowEffect BlurRadius="10" Color="Black" Direction="0" Opacity="0.6" RenderingBias="Performance" ShadowDepth="0" />
</Setter.Value>
</Setter>
</Trigger>
<Trigger Property="Button.IsMouseOver" Value="True">
<Setter Property="UIElement.Effect">
<Setter.Value>
<DropShadowEffect BlurRadius="10" Color="White" Direction="0" Opacity="0.6" RenderingBias="Performance" ShadowDepth="0" />
</Setter.Value>
</Setter>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
回答by Joee
Simply try this code
只需尝试此代码
<Button Name="btn_Refresh" Grid.Column="0" Height="25" Width="25" HorizontalAlignment="Right" VerticalAlignment="Center" Background="White" Margin="0,0,10,0" Click="btn_Refresh_Click">
<Button.Content>
<Grid>
<Path Width="15" Height="15" Fill="Blue" Stretch="Fill" Data="F1 M 38,20.5833C 42.9908,20.5833 47.4912,22.6825 50.6667,26.046L 50.6667,17.4167L 55.4166,22.1667L 55.4167,34.8333L 42.75,34.8333L 38,30.0833L 46.8512,30.0833C 44.6768,27.6539 41.517,26.125 38,26.125C 31.9785,26.125 27.0037,30.6068 26.2296,36.4167L 20.6543,36.4167C 21.4543,27.5397 28.9148,20.5833 38,20.5833 Z M 38,49.875C 44.0215,49.875 48.9963,45.3932 49.7703,39.5833L 55.3457,39.5833C 54.5457,48.4603 47.0852,55.4167 38,55.4167C 33.0092,55.4167 28.5088,53.3175 25.3333,49.954L 25.3333,58.5833L 20.5833,53.8333L 20.5833,41.1667L 33.25,41.1667L 38,45.9167L 29.1487,45.9167C 31.3231,48.3461 34.483,49.875 38,49.875 Z " Margin="-8.3,-2,-5.701,0"/>
</Grid>
</Button.Content>
</Button>
回答by Ilan
The simple way in WPF:
WPF中的简单方法：
Create a button image with Photoshop or other programs.
Place it on your window and use the
MouseEnterandMouseLeaveevents.private void img1_MouseEnter(object sender, MouseEventArgs e) { Cursor = Cursors.Hand; } private void img1_MouseLeave(object sender, MouseEventArgs e) { Cursor = Cursors.Arrow; }
使用 Photoshop 或其他程序创建按钮图像。
将它放在您的窗口上并使用
MouseEnter和MouseLeave事件。private void img1_MouseEnter(object sender, MouseEventArgs e) { Cursor = Cursors.Hand; } private void img1_MouseLeave(object sender, MouseEventArgs e) { Cursor = Cursors.Arrow; }
