Python 'numpy.ndarray' 对象没有属性 'index'
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'numpy.ndarray' object has no attribute 'index'
提问by Vehicom0607
I'm trying to find the index of v but it always gives me:'numpy.ndarray' object has no attribute 'index'
I've tried:
TypeError: slice indices must be integers or None or have an __index__ method. How to resolve it?How to find the index of an array within an array.
Finding the index of an item given a list containing it in Python
我试图找到 v 的索引，但它总是给我：'numpy.ndarray' object has no attribute 'index'
我试过：类型错误
：切片索引必须是整数或无或有一个 __index__ 方法。如何解决？如何在数组中查找数组的索引。
在给定包含它的列表的 Python 中查找项目的索引
none of them have answered my question
他们都没有回答我的问题
v = np.random.randn(10)
print(v)
maximum = np.max(v)
minimum = np.min(v)
print(maximum, minimum)
v.index(maximum, minimum)
edit: Oh, crap i put ma instead of maximum my bad. I just started programing then.
编辑：哦，废话，我把 ma 而不是最大的我的坏。那时我才开始编程。
回答by seralouk
First of all, indexis a list method. Here vis a numpy array and you need to do the following:
首先，index是一个列表方法。这v是一个 numpy 数组，您需要执行以下操作：
v = np.random.randn(10)
print(v)
maximum = np.max(v)
minimum = np.min(v)
print(maximum, minimum)
index_of_maximum = np.where(v == maximum)
index_of_minimum = np.where(v == minimum)
Get the elements using these indices:
使用这些索引获取元素：
v[index_of_minimum]
v[index_of_maximum]
Verify using assert:
使用断言验证：
assert(v[index_of_maximum] == v.max())
assert(v[index_of_minimum] == v.min())
回答by ColinMac
If you are using Numpy:
如果您使用的是 Numpy：
values = np.array([3,6,1,5])
index_min = np.argmin(values)
print(index_min)
returns the index of 2.
返回 2 的索引。
