Javascript 用字母数字、空格和标点符号匹配字符串的正则表达式
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A regex to match strings with alphanumeric, spaces and punctuation
提问by jdimona
I need a regular expression to match strings that have letters, numbers, spaces and some simple punctuation (.,!"'/$). I have ^[A-Za-z0-9 _]*[A-Za-z0-9][A-Za-z0-9 _]*$and it works well for alphanumeric and spaces but not punctuation. Help is much appreciated.
我需要一个正则表达式来匹配包含字母、数字、空格和一些简单标点符号 ( .,!"'/$) 的字符串。我有^[A-Za-z0-9 _]*[A-Za-z0-9][A-Za-z0-9 _]*$，它适用于字母数字和空格，但不适用于标点符号。非常感谢帮助。
回答by CaNNaDaRk
Just add punctuation and other characters inside classes (inside the square brackets):
只需在类内（方括号内）添加标点符号和其他字符：
[A-Za-z0-9 _.,!"'/$]*
This matches every string containing spaces, _, alphanumerics, commas, !, ", $, ... Pay attention while adding some special characters, maybe you need to escape them: more info here
这匹配每个包含空格、_、字母数字、逗号、!、"、$、...的字符串，在添加一些特殊字符时要注意，也许你需要对它们进行转义：更多信息在这里
回答by Tim Pietzcker
Assuming from your regex that at least one alphanumeric character must be present in the string, then I'd suggest the following:
假设根据您的正则表达式，字符串中必须至少存在一个字母数字字符，那么我建议如下：
/^(?=.*[A-Z0-9])[\w.,!"'\/$ ]+$/i
The (?=.*[A-Z0-9])lookahead checks for the presence of one ASCII letter or digit; the nest character class contains all ASCII alphanumerics including underscore (\w) and the rest of the punctuation characters you mentioned. The slash needs to be escaped because it's also used as a regex delimiter. The /imodifier makes the regex case-insensitive.
该(?=.*[A-Z0-9])先行检查一个ASCII字母或数字的存在; 嵌套字符类包含所有 ASCII 字母数字，包括下划线 ( \w) 和您提到的其余标点符号。斜线需要转义，因为它也用作正则表达式分隔符。该/i修改使正则表达式不区分大小写。
回答by Tarun Gupta
<script type="text/javascript">
check("hello dfdf asdjfnbusaobfdoad fsdihfishadio fhsdhf iohdhf");
function check(data){
var patren=/^[A-Za-z0-9\s]+$/;
if(!(patren.test(data))) {
alert('Input is not alphanumeric');
return false;
}
alert(data + " is good");
}
</script>
