java 如何从Android的xml字符串资源中检索二维数组？
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How to retrieve 2D array from xml string resource for Android?
提问by Imon
Suppose I have stored a 2 dimensional array in android resource as shown below. How can I get them in a java collection like Arraylist?
假设我在 android 资源中存储了一个二维数组，如下所示。如何将它们放入像 Arraylist 这样的 Java 集合中？
<resources>
<string-array name="countries_array">
<item>
<name>Bahrain</name>
<code>12345</code>
</item>
<item>
<name>Bangladesh</name>
<code>54545</code>
</item>
<item>
<name>India</name>
<code>54455</code>
</item>
</string-array>
</resources>
For example in case of 1 dimensional array we can do it using
例如，在一维数组的情况下，我们可以使用
getResources().getStringArray(R.array.countries_array);
When the countries_array is like
当 country_array 就像
<resources>
<string-array name="countries_array">
<item>Bahrain</item>
<item>Bangladesh</item>
<item>India</item>
</string-array>
</resources>
回答by Squonk
The <string-array>element of a resources file can only be used for single dimension arrays. In other words, everything between <item>and </item>is considered to be a single string.
<string-array>资源文件的元素只能用于一维数组。换句话说，<item>和之间的所有内容都</item>被视为单个字符串。
If you want to store data in the way you describe (effectively pseudo-XML), you'll need to get the items as a single String[]using getStringArray(...)and parse the <name>and <codes>elements yourself.
如果您想以您描述的方式（实际上是伪 XML）存储数据，您需要将这些项目作为单个String[]usinggetStringArray(...)并自己解析<name>和<codes>元素。
Personally I'd possibly go with a de-limited format such as...
就我个人而言，我可能会使用分隔格式，例如...
<item>Bahrain,12345</item>
...then just use split(...).
...然后只需使用split(...).
Alternatively, define each <item>as a JSONObject such as...
或者，将每个定义<item>为 JSONObject，例如...
<item>{"name":"Bahrain","code":"12345"}</item>
回答by Basem
Instead of multi-valued entries, I wrote about anotherapproach where you can store your complex objects as an array, then suffix the name with an incremental integer. Loop through them and create a list of strongly-typed objects from there if needed.
我写的不是多值条目，而是另一种方法，您可以将复杂对象存储为数组，然后使用增量整数作为名称后缀。如果需要，循环遍历它们并从那里创建强类型对象列表。
<resources>
<array name="categories_0">
<item>1</item>
<item>Food</item>
</array>
<array name="categories_1">
<item>2</item>
<item>Health</item>
</array>
<array name="categories_2">
<item>3</item>
<item>Garden</item>
</array>
<resources>
Then you can create a static method to retrieve them:
然后你可以创建一个静态方法来检索它们：
public class ResourceHelper {
public static List<TypedArray> getMultiTypedArray(Context context, String key) {
List<TypedArray> array = new ArrayList<>();
try {
Class<R.array> res = R.array.class;
Field field;
int counter = 0;
do {
field = res.getField(key + "_" + counter);
array.add(context.getResources().obtainTypedArray(field.getInt(null)));
counter++;
} while (field != null);
} catch (Exception e) {
e.printStackTrace();
} finally {
return array;
}
}
}
It can be consumed like this now:
现在可以这样食用：
for (TypedArray item : ResourceHelper.getMultiTypedArray(this, "categories")) {
Category category = new Category();
category.ID = item.getInt(0, 0);
category.title = item.getString(1);
mCategories.add(category);
}
