C++ remove_if 在对象向量上

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时间:2020-08-28 17:47:45  来源:igfitidea点击:

C++ remove_if on a vector of objects

c++vectorstlpredicate

提问by Jordan

I have a vector (order is important) of objects (lets call them myobj class) where I'm trying to delete multiple objects at a time.

我有一个对象的向量(顺序很重要)(让我们称它们为 myobj 类),我试图一次删除多个对象。

class vectorList
{

    vector<*myobj> myList; 
};

class myobj
{

    char* myName;
    int index;
    bool m_bMarkedDelete;
}

I was thinking that the best way to do this would be to mark specific myobj objects for deletion and then call myList.remove_if() on the vector. However, I'm not exactly sure how to use predicates and such for this. Should I create a member variable in the object which allows me to say that I want to delete the myobj and then create a predicate which checks to see if the member variable was set?

我认为最好的方法是将特定的 myobj 对象标记为删除,然后在向量上调用 myList.remove_if() 。但是,我不确定如何为此使用谓词等。我应该在对象中创建一个成员变量,它允许我说我想删除 myobj 然后创建一个谓词来检查是否设置了成员变量?

How do I implement the predicate as a part of the vectorList class?

如何将谓词实现为 vectorList 类的一部分?

回答by Benjamin Lindley

Should I create a member variable in the object which allows me to say that I want to delete the myobj and then create a predicate which checks to see if the member variable was set?

我应该在对象中创建一个成员变量,它允许我说我想删除 myobj 然后创建一个谓词来检查是否设置了成员变量?

Haven't you already done that? Isn't that what m_bMarkedDeleteis for? You would write the predicate like this:

你不是已经这样做了吗?不m_bMarkedDelete就是为了这个吗?你可以这样写谓词:

bool IsMarkedToDelete(const myobj & o)
{
    return o.m_bMarkedDelete;
}

Then:

然后:

myList.erase(
    std::remove_if(myList.begin(), myList.end(), IsMarkedToDelete),
    myList.end());

Or, using lambdas:

或者,使用 lambda 表达式:

myList.erase(
    std::remove_if(myList.begin(), myList.end(),
        [](const myobj & o) { return o.m_bMarkedDelete; }),
    myList.end());

If your class doesn't actually have that member, and you're asking us if it should, then I would say no. What criteria did you use to decide to mark it for deletion? Use that same criteria in your predicate, for example:

如果你的班级实际上没有那个成员,而你问我们是否应该,那么我会说不。您使用什么标准来决定将其标记为删除?在谓词中使用相同的条件,例如:

bool IndexGreaterThanTen(const myobj & o)
{
    return o.index > 10;
}

note-- The functions I've written are of course invalid since all your members are private. So you'll need some way to access them.

注意——我写的函数当然是无效的,因为你所有的成员都是私有的。因此,您需要某种方式来访问它们。

回答by AJG85

A predicate is basically a conditional comparison. It can be a function or object. Here's an example using new C++ lambdas. This code will go through the vector and remove the values equal to 3.

谓词基本上是条件比较。它可以是一个函数或对象。这是一个使用新 C++ lambda 的示例。此代码将遍历向量并删除等于 3 的值。

int arg[6] = {1, 2, 3, 3, 3, 5};
std::vector<int> vec(arg, arg+6);
vec.erase(
   std::remove_if(
      vec.begin(), vec.end(),
      [](int i){ return i == 3;}),
   vec.end());

Edit:For pointers let's say you had a vector or interfaces you could set them to nullptrthen remove them in a batch with pretty much the same code. In VS2008 you won't have lambdas so make a comparison predicate function or struct instead.

编辑:对于指针,假设您有一个向量或接口,您可以将它们设置为nullptr然后使用几乎相同的代码批量删除它们。在 VS2008 中,您将没有 lambda,因此请改用比较谓词函数或结构。

bool ShouldDelete(IAbstractBase* i)
{
    return i == nullptr;
    // you can put whatever you want here like:
    // return i->m_bMarkedDelete;
}

std::vector<IAbstractBase*> vec;
vec.erase(
   std::remove_if(
      vec.begin(), vec.end(),
      ShouldDelete),
   vec.end());