java 如何检查输入到数组中的用户是否为回文？
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How can I check if the user entered in an array is palindrome or not?
提问by Angela Vinagrera
I need help guys I have been checking on google for similar question but I cant find the most suitable answer for this. Here is my output.
我需要帮助我一直在谷歌上检查类似问题的人，但我找不到最合适的答案。这是我的输出。
Enter 3 Elements
23
Is a palindrome
22
Is not a palindrome
11
Is not a palindrome
The program:
该程序：
public static void main(String [] args)
{
int number = 0;
int reverse =0;
int numCopy = 0;
Scanner scan = new Scanner(System.in);
System.out.println("Enter how many numbers you want to enter");
int num = scan.nextInt();
System.out.println("Enter "+num +" Elements");
numCopy = num;
int[] array = new int[num];
for(int i = 0; i < num; i++)
{
array[i] = scan.nextInt();
int digit = numCopy % 10;
numCopy = numCopy / 10;
reverse = (reverse * 10) +digit;
if(num == reverse)
{
System.out.println("Is a palindrome");
}
else
{
System.out.println("Is not a palindrome");
}
}
}
回答by Jay
A Palindrome by definition is the same forwards and back so 11would be and 22would be. 23would not etc.
回文的定义是相同的向前和向后所以11会和22会。23不会等
Quick easy psudo code for checking if Palindrome as a STRING:
用于检查回文是否为字符串的快速简单伪代码：
function isPalin(string str)
if(str.length() == 0) {
return true;
}
int end = str.length() - 1;
int start = 0;
while(start < end) {
if(str[start++] != str[end--]) {
return false;
}
}
return true;
If you have numbers just covert it to a string then use the function.
如果您有数字只是将其转换为字符串，则使用该函数。
回答by adiggo
A palindrome, for example, we need to consider two difference case: AA and ABA. These two are all palindrome. So for integers, you need to confirm its length is even or odd. Then check from both sides: start, end.
以回文为例，我们需要考虑两种不同的情况：AA 和 ABA。这两个都是回文。所以对于整数，你需要确认它的长度是偶数还是奇数。然后从双方检查：开始，结束。
This should get the correct result.
这应该得到正确的结果。
回答by user3487063
you should have your program like below:
你应该有你的程序如下：
public static void main(String[] args)
{
int number = 0;
int reverse =0;
int numCopy = 0;
Scanner scan = new Scanner(System.in);
System.out.println("Enter how many numbers you want to enter");
int num = scan.nextInt();
System.out.println("Enter "+num +" Elements");
numCopy = num;
String[] array = new String[num];
for(int i = 0; i < num; i++)
{
array[i] = new Integer(scan.nextInt()).toString();
String rev="";
for(int k=array[i].length()-1;k>=0;k--){
rev +=array[i].charAt(k);
}
if(array[i].equals(rev))
{
System.out.println("Is a palindrome");
}
else
System.out.println("Is not a palindrome");
}
}
