string 在 MIPS 中打印字符串和变量
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Printing a string and variable in MIPS
提问by hodgesmr
Here's the C representation of what I'm trying to do in MIPS assembly:
这是我在 MIPS 程序集中尝试执行的操作的 C 表示：
printf ("x=%d\n", x);
I know that I can do a syscall to easily print x= and I can also do a syscall to print the int x (which is stored in a register). However, that prints them like this (let's say x is 5):
我知道我可以做一个系统调用来轻松打印 x= ，我也可以做一个系统调用来打印 int x （它存储在寄存器中）。但是，它会像这样打印它们（假设 x 是 5）：
x=
5
x=
5
How can I make them print on the same line?
如何让它们打印在同一行上？
回答by Paul R
Look at the Fibonacci.asm example: http://courses.missouristate.edu/KenVollmar/MARS/Fibonacci.asm- it seems to be a good example of exactly what you need to do - look at the part near the print:label. It looks like you needs syscall 4for printing the x =part and syscall 1for printing the integer itself.
查看 Fibonacci.asm 示例：http: //courses.missouristate.edu/KenVollmar/MARS/Fibonacci.asm- 这似乎是您需要做什么的一个很好的示例 - 查看print:标签附近的部分。看起来您需要syscall 4打印x =零件和syscall 1打印整数本身。
回答by ndim
Use a syscall for printing the x=which does not add a line feed.
使用系统调用来打印x=不添加换行符的。
What that syscall might be is system specific, and you are not mentioning anything about the system.
该系统调用可能是特定于系统的，并且您没有提及有关系统的任何内容。
回答by WhirlWind
If you print with two separate characters, 'x' and '=', you should avoid the newline problem.
如果使用两个单独的字符 'x' 和 '=' 打印，则应避免换行问题。
