javascript 来自带有 angularjs 的 json 的 ng-options

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时间:2020-10-27 17:19:46  来源:igfitidea点击:

ng-options from a json with angularjs

javascriptjsonangularjs

提问by Pacuraru Daniel

i got a json that looks like this

我有一个看起来像这样的 json

[{"partner_id":"8","partner_name":"Company1","partner_location":["Place1","Place2","Place3"],"partner_user":["User1","User2","User3"]},{"partner_id":"9","partner_name":"Company2","partner_location":["Place4","Place5"],"partner_user":["User4","User5"]}]

Now i want to do something like this. I have 2 dropdowns and i want the first one to be filled with the partner_name from my 2 lists so it has to look like this

现在我想做这样的事情。我有 2 个下拉列表,我希望第一个用我的 2 个列表中的 partner_name 填充,所以它必须看起来像这样

<select>
    <option value="8">Company1</option>
    <option value="9">Company2</option>
</select>

but i want it to be selected already with a value that i set inside service_id. I understand you can do this somehow like this

但我希望它已经被选中,我在里面设置了一个值service_id。我知道你可以像这样以某种方式做到这一点

<select ng-options="partner for partner in jsonPartners" ng-model="service_id"></select>

but when i do this, i have inside my select 2 options called [object Object]

但是当我这样做时,我在我的选择 2 个选项中调用了 [object Object]

And the 2nd select is more tricky, i want it to have the locations of what the id was selected in my 1st select. So if i selected Company1, than it should be filled with Place1, Place2, Place3and if i selected Company2, it should be filled with Place4, Place5.

第二个选择更棘手,我希望它具有在我的第一个选择中选择的 id 的位置。因此,如果我选择了Company1,则应该填充,Place1, Place2, Place3如果我选择了Company2,则应该填充Place4, Place5

Thank you in advance, Daniel!

提前谢谢你,丹尼尔!

回答by AlwaysALearner

HTML

HTML

<div ng-app="myApp" ng-controller="ctrl">
    <select ng-options="partner as partner.partner_name 
    for partner in jsonPartners" ng-model="service_id"></select>

    <select ng-options="place for place in service_id.partner_location" 
    ng-model="service_location"></select>
</div>

JS

JS

var app = angular.module('myApp', []);

function ctrl($scope){
    $scope.jsonPartners = [{"partner_id":"8", ..},{"partner_id":"9", ..}]

    $scope.service_id = $scope.jsonPartners[1];
}

fiddle

fiddle

回答by Maxim Shoustin

I would add the ng-changeto select 1st item by default:

ng-change默认情况下,我会添加以选择第一项:

JS controller

JS控制器

$scope.jsonPartners = [{
    "partner_id": "8",
    "partner_name": "Company1",
    "partner_location": ["Place1", "Place2", "Place3"],
    "partner_user": ["User1", "User2", "User3"]
}, {
    "partner_id": "9",
    "partner_name": "Company2",
    "partner_location": ["Place4", "Place5"],
    "partner_user": ["User4", "User5"]
}];


$scope.partner = $scope.jsonPartners[0];
$scope.place = $scope.partner.partner_location[0];

$scope.onChange = function(partner){       
  $scope.place = partner.partner_location[0];
}

HTML

HTML

<div ng-controller="fessCntrl">
     <select ng-model="partner"          
     ng-options="partner as partner.partner_name for partner in jsonPartners"
         ng-change="onChange(partner)"
     ></select>

     <select ng-model="place"         
             ng-options="place as place for place in partner.partner_location"         
      ></select>
</div>

Demo Fiddle

演示 Fiddle