在java中需要安全的头代码
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/18798179/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Need secure header code in java
提问by user2777452
I need to access the secure webservice. I need to pass the secure header in the soap request.Please help me to provide the custom secure header code in java.
我需要访问安全网络服务。我需要在soap请求中传递安全标头。请帮助我在java中提供自定义安全标头代码。
Requirement:
要求:
<soapenv:Header>
<wsse:Security xmlns:wsse="http://schemas.xmlsoap.org/ws/2002/07/secext">
<wsse:UsernameToken xmlns:wsu="http://schemas.xmlsoap.org/ws/2002/07/utility">
<wsse:Username>XYZ</wsse:Username>
<wsse:Password Type="wsse:PasswordText">security</wsse:Password>
</wsse:UsernameToken>
i Appreciate if any one help me on this.`
如果有人帮助我,我很感激。`
回答by Mohsen Heydari
Your question is not clear!
Take a look at the articleand this topic.
BTW
If you mean having security on transport level protocols like HTTPS , you may see Apache CXF SSl support.
If you mean WS-Security above and beyond transport level protocols, such as XML-Encryption or X509 you may see Apache CXF WS-Security
你的问题不清楚!
看看这篇文章和这个话题。
顺便说一句,
如果您的意思是在 HTTPS 等传输级协议上具有安全性,您可能会看到Apache CXF SSL 支持。
如果您的意思是 WS-Security 超越传输级协议,例如 XML-Encryption 或 X509,您可能会看到Apache CXF WS-Security
回答by Dennis Sosnoski
Seems pretty clear that you want to add a UsernameToken security header. There are at least a couple of different ways of doing this. If you have a WSDL service definition which includes the WS-SecurityPolicy component you can just set the appropriate properties to define the username and password values, as shown in thisarticle
似乎很清楚您要添加 UsernameToken 安全标头。至少有几种不同的方法可以做到这一点。如果你有一个WSDL服务定义,其中包括你可以设置相应属性来定义用户名和密码值WS-安全组件,如图此文章
If you want to set this up directly (without using a policy), you can do so in your client code. Here's a sample of how this would work:`
如果您想直接设置它(不使用策略),您可以在您的客户端代码中进行设置。这是如何工作的示例:`
// create the client stub
MyService service = new MyService();
MyServicePort stub = service.getMyServicePort();
// configure UsernameToken security handling
Map<String, Object> props = new HashMap<String, Object>();
props.put(WSHandlerConstants.ACTION, WSHandlerConstants.USERNAME_TOKEN);
props.put(WSHandlerConstants.PASSWORD_TYPE, WSConstants.PW_TEXT);
props.put(WSHandlerConstants.USER, "XYZ");
props.put(WSHandlerConstants.PW_CALLBACK_CLASS, PasswordHandler.class.getName());
WSS4JOutInterceptor wssOut = new WSS4JOutInterceptor(props);
Client client = ClientProxy.getClient(stub);
client.getOutInterceptors().add(wssOut);
...
...
/**
* Callback for password used by WS-Security UsernameToken.
*/
public static class PasswordHandler implements CallbackHandler
{
public void handle(Callback[] callbacks) {
for (int i = 0; i < callbacks.length; i++) {
WSPasswordCallback pc = (WSPasswordCallback)callbacks[i];
pc.setPassword("security");
}
}
}
`
`
回答by user2777452
thanks you for your support. I used the following code for secure header , it is working fine for me.
感谢您的支持。我将以下代码用于安全标头,它对我来说很好用。
SOAPHeaderElement wsseSecurity = new SOAPHeaderElement(new PrefixedQName("http://schemas.xmlsoap.org/ws/2002/07/secext","Security", "wsse"));
wsseSecurity.setMustUnderstand(false);
wsseSecurity.setActor(null);
SOAPElement sub = wsseSecurity.addChildElement("UsernameToken");
sub.setAttribute("xmlns:wsu", "http://schemas.xmlsoap.org/ws/2002/07/utility");
SOAPElement userElement = sub.addChildElement("Username");
userElement.addTextNode("XYZ");
SOAPElement pwdElement = sub.addChildElement("Password");
pwdElement.setAttribute("Type", "wsse:PasswordText");
pwdElement.addTextNode("security");
_stub.setHeader(wsseSecurity);