通过 Java 替换 XML 节点
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Replacing XML node via Java
提问by Ondrej Sotolar
I wan to replace a node in XML document with another and as a consequence replace all it's children with other content. Following code should work, but for an unknown reason it doesn't.
我想用另一个替换 XML 文档中的一个节点，因此用其他内容替换它的所有子节点。以下代码应该可以工作，但由于未知原因，它不起作用。
File xmlFile = new File("c:\file.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(xmlFile);
doc.getDocumentElement().normalize();
NodeList nodes = doc.getElementsByTagName("NodeToReplace");
for (int i = 0; i < nodes.getLength(); i++) {
NodeList children = nodes.item(i).getChildNodes();
for (int j = 0; j < children.getLength(); j++) {
nodes.item(i).removeChild(children.item(j));
}
doc.renameNode(nodes.item(i), null, "MyCustomTag");
}
EDIT-
编辑-
After debugging it for a while, I sovled it. The problem was in moving index of the children array elmts. Here's the code:
调试了一段时间后，我解决了它。问题在于移动子数组 elmts 的索引。这是代码：
NodeList nodes = doc.getElementsByTagName("NodeToReplace");
for (int i = 0; i < nodes.getLength(); i++) {
NodeList children = nodes.item(i).getChildNodes();
int len = children.getLength();
for (int j = len-1; j >= 0; j--) {
nodes.item(i).removeChild((Node) children.item(j));
}
doc.renameNode(nodes.item(i), null, "MyCustomTag");
}
回答by Thor84no
Try using replaceChild to do the whole hierarchy at once:
尝试使用 replaceChild 一次完成整个层次结构：
NodeList nodes = doc.getElementsByTagName("NodeToReplace");
for (int i = 0; i < nodes.getLength(); i++) {
Node node = nodes.item(i);
Node newNode = // Create your new node here.
node.getParentNode().replaceChild(newNode, node);
}
回答by Venkat
Easy way to do is using regular expression.
简单的方法是使用正则表达式。
String payload= payload.replaceAll("<payload>([^<]*)</payload>", "<payload>NODATA</payload>");
This will make sure all the payload nodes contents are replaced with NODATA
这将确保所有有效负载节点的内容都替换为 NODATA
