node.js 快递中路由的单独文件
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separate file for routes in express
提问by svnm
I was wondering how do I move all of my api routes in express into a separate routes.jsfile from my server.jsfile
我想知道如何将 express 中的所有 api 路由移动到routes.js与我的server.js文件不同的文件中
I have a long list of api routes using app.use()for each route. So each route is in its own file, e.g. movies.js, movie.jsbut when I list these it makes for a long list in server.js
我有一长串app.use()用于每条路线的 api路线。所以每条路线都在它自己的文件中，例如movies.js，movie.js但是当我列出这些时，它会在server.js
So I want to remove the list of api endpoints section from the below server.jsout to a routes.jsfile.
所以我想将下面的 api 端点列表部分删除server.js到一个routes.js文件中。
Here is what I have currently:
这是我目前所拥有的：
server.js
服务器.js
import path from 'path'
import express from 'express'
import webpack from 'webpack'
import webpackDevMiddleware from 'webpack-dev-middleware'
import webpackConfig from './webpack.config.dev'
const app = express();
/* api endpoints, can be many more, I want them in routes.js */
app.use('/api/movies', require('./src/api/routes/movies'))
app.use('/api/movie', require('./src/api/routes/movie'))
app.use(webpackDevMiddleware(webpack(webpackConfig), {
publicPath: webpackConfig.output.publicPath
}));
app.use('/public', express.static(__dirname + '/public'))
app.get('*', function(req, res) {
res.sendFile(path.join(__dirname, 'index.html'));
});
app.listen(3000, 'localhost', function (err) {
if (err) {
console.log(err);
return;
}
})
An example route
示例路线
movies.js
电影.js
var express = require('express');
var request = require("request");
var router = express.Router();
router.get('/', function(req, res) {
res.json({})
});
module.exports = router;
回答by Mukesh Sharma
You can try to use the following modular approach. Define controller files having logic per feature. e.g. movie.
您可以尝试使用以下模块化方法。定义具有每个功能逻辑的控制器文件。例如电影。
movieController.js
电影控制器.js
module.exports = {
getMovie : function(req, res){
//do something
},
getMovies : function(req, res){
//do something
},
postMovie : function(req, res){
//do something
}
}
Then, reference that controller in routes files and simply plug those functions.
然后，在路由文件中引用该控制器并简单地插入这些函数。
routes.js
路由.js
var express = require('express');
var movieCtrl = require('./movieController');
var router = express.Router();
router.route('/movie').get(movieCtrl.getMovie);
router.route('/movie').post(movieCtrl.postMovie);
router.route('/movies').get(movieCtrl.getMovies);
module.exports = router;
And, in app.js, mount the routes to suitable location, e.g. /api
并且，在 app.js 中，将路由挂载到合适的位置，例如 /api
app.js
应用程序.js
var routes = require('./routes');
app.use('/api', routes);
