C# 在 VB.NET 中声明一个十六进制常量
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原文地址: http://stackoverflow.com/questions/10240587/
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Declaring a hex constant in VB.NET
提问by Ali
采纳答案by Niranjan Singh
C# uses 0xand VB.NETuses &Has the prefix to specify hexadecimal numbers.try this.
C# 使用0x和VB.NET使用&H作为前缀来指定十六进制数字。尝试这个。
Public Const temp As Integer = &HE6359A60
Sub Main
End Sub
And it could be as Uint also:
它也可以是 Uint：
Public Const temp As UInt32 = &HE6359A60UI
Sub Main
End Sub
Check MSDN's Type Characters (Visual Basic)documentation for defining hexadecimal and octal literals:
检查 MSDN 的类型字符 (Visual Basic)文档以定义十六进制和八进制文字：
The compiler normally construes an integer literal to be in the decimal (base 10) number system. You can force an integer literal to be hexadecimal (base 16)with the &H prefix, and you can force it to be octal (base 8)with the &O prefix. The digits that follow the prefix must be appropriate for the number system.
编译器通常将整数文字解释为十进制（基数为 10）的数字系统。您可以使用&H 前缀强制整数文字为十六进制（以16 为底），也可以使用&O 前缀将其强制为八进制（以 8为底）。前缀后面的数字必须适用于数字系统。
References:
参考：
- Hex number (not ASCII hex value) to string in VB.NET(Stack Overflow)
- What does &H57 represent and how can I translate it for C#?(Stack Overflow)
回答by Alex
Public Const temp As Integer = &H6359A60
Prefix it with &H
前缀为 &H
