Python 将单词转换为字符列表
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convert a word to a list of chars
提问by user1103294
I can split a sentence into individual words like so:
我可以将一个句子拆分为单个单词，如下所示：
string = 'This is a string, with words!'
string.split(" ")
['This', 'is', 'a', 'string,', 'with', 'words!']
But I don't know how to split a word into letters:
但我不知道如何将单词拆分为字母：
word = "word"
word.split("")
Throws me an error. Ideally I want it to return ['w','o','r','d'] thats why the split argument is "".
给我一个错误。理想情况下，我希望它返回 ['w','o','r','d'] 这就是为什么 split 参数是“”。
回答by dm03514
list(word)
list(word)
you can pass it to list
你可以把它传递给 list
>>> list('word')
['w', 'o', 'r', 'd']
回答by iblazevic
>>> s = "foobar"
>>> list(s)
['f', 'o', 'o', 'b', 'a', 'r']
回答by CraigTeegarden
You can iterate over each letter in a string like this:
您可以像这样遍历字符串中的每个字母：
>>> word = "word"
>>> for letter in word:
... print letter;
...
w
o
r
d
>>>
回答by Apollo SOFTWARE
In python send it to
在python中将其发送到
list(word)
回答by ovgolovin
In Python string is iterable. This means it supports special protocol.
在 Python 中，字符串是可迭代的。这意味着它支持特殊协议。
>>> s = '123'
>>> i = iter(s)
>>> i
<iterator object at 0x00E82C50>
>>> i.next()
'1'
>>> i.next()
'2'
>>> i.next()
'3'
>>> i.next()
Traceback (most recent call last):
File "<pyshell#7>", line 1, in <module>
i.next()
StopIteration
listconstructor may build list of any iterable. It relies on this special method nextand gets letter by letter from string until it encounters StopIteration.
list构造函数可以构建任何可迭代的列表。它依赖于这种特殊的方法next，从字符串中逐个字母地获取，直到遇到StopIteration.
So, the easiest way to make a list of letters from string is to feed it to listconstructor:
因此，从字符串制作字母列表的最简单方法是将其提供给list构造函数：
>>> list(s)
['1', '2', '3']
