从 Java Web 服务客户端获取原始 XML 响应
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Getting raw XML response from Java web service client
提问by FrustratedWithFormsDesigner
I am trying to get the raw XML response from a web service, instead of the usual set of POJOs.
我试图从 Web 服务中获取原始 XML 响应，而不是通常的 POJO 集。
I am using a webservice client that I generated (so I have access to the client's code) from a WSDL and some schemas. The client is generated in RAD 7.5, I think using JAX-WS. I've been looking at the client code itself, but I'm not even sure if the client code ever handles raw XML or if it passes it off to other libraries.
我正在使用我从 WSDL 和一些模式生成的网络服务客户端（所以我可以访问客户端的代码）。客户端是在 RAD 7.5 中生成的，我认为使用 JAX-WS。我一直在查看客户端代码本身，但我什至不确定客户端代码是否曾经处理过原始 XML 或者是否将其传递给其他库。
回答by Ilya
You can do it using
你可以使用
javax.xml.ws.handler.soap.SOAPHandler<javax.xml.ws.handler.soap.SOAPMessageContext>
you can simply get message using SOAPMessageContext#getMessage()and convert message to String using method
您可以简单地SOAPMessageContext#getMessage()使用方法获取消息并使用方法将消息转换为字符串
public static String getXmlMessage(SOAPMessage message) throws Exception
{
ByteArrayOutputStream os = new ByteArrayOutputStream();
message.writeTo(os);
final String encoding = (String) message.getProperty(SOAPMessage.CHARACTER_SET_ENCODING);
if (encoding == null)
{
return new String(os.toByteArray());
}
else
{
return new String(os.toByteArray(), encoding);
}
}
Also you can read here about SOAP handler on client side
Article
您也可以在此处阅读有关客户端文章的SOAP 处理程序
